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Nat2105 [25]
3 years ago
11

Dns uses udp instead of tcp. if a dns packet is lost, there is no automatic recovery. does this cause a problem, and if so, how

is it solved?
Computers and Technology
1 answer:
grandymaker [24]3 years ago
7 0
Packet loss is typically resolved by time-outs and retries. For applications where a duplicate operation doesn't matter this is acceptable.
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Set-In-Order includes making changes to the layout of the area.A) TrueB) False
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Answer:

A) True

Explanation:

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Set-In-Order specifically deals with entities in the workplace apparently labeled after being well arranged in their respective places.

Hence, it is TRUE that Set-In-Order includes making changes to the layout of the area.

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Write a program that prompts the user to enter a string and displays the maximum consecutive increasingly ordered substring. Ana
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Answer:

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// Program is written in Java Programming Language

// Comments are used for explanatory purpose

// Comments marked x represents simple statements

// Comments marked y represents single loop

// Program starts here

import java.util.*;

public class MaxOrder {

public static void main(String args [] ) {

Scanner accept = new Scanner(System.in);

LinkedList<Character> maxtext = new LinkedList<>();

LinkedList<Character> textlist = new LinkedList<>();

System.out.print("Enter a text: ");

String text = accept.nextLine();

// Find the maximum consecutive increasingly ordered substring

for (int i = 0; i < text.length(); i++) { // y1

if (textlist.size() > 1 && text.charAt(i) <= textlist.getLast() && textlist.contains(text.charAt(i))) {

textlist.clear(); // x

}

textlist.add(text.charAt(i)); // x

if (textlist.size() > maxtext.size()) { // x

maxtext.clear();

maxtext.addAll(list);

}

}

// Display the maximum consecutive

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for (Character ch: maxtext) { // y2

System.out.print(ch); // x

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System.out.println();

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b. Analysing the time complexity

In single loop marked y1, there are 3 simple statements ----- 1

In single loop marked y2, there is 1 simple statement --_--- 2

In (1) above,

1 single loop * 3 simple statements = 3;

*

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So, we have

T(n) = O(n) Linear time

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