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3 years ago

6

Choose the atom that has the smallest atomic radius. Rb Na K Li

2 answers:

vesna_86 [32]3 years ago

8 0

The answer is Rb.....................................

sdas [7]3 years ago

6 0

Answer: Option (d) is the correct answer.

Explanation:

The given elements are Rb, Na, K and Li and all these elements are group 1 elements.

These are also known as alkali metals. These elements are placed in the order from top to bottom as Li, Na, K, Rb.

It is known that when we move down a group then there is increase in the size of atom. As a result, atomic radius also increases.

Thus, atom at the top which is lithium (Li) will have the smallest atomic radius.

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inessss [21]

Actual volume=Final Volume-initial volume

$\\ \sf\longmapsto 50ml-30ml=20ml$

Now

$\\ \sf\longmapsto Density=\dfrac{Mass}{Volume}$

$\\ \sf\longmapsto Density=\dfrac{10}{20}$

$\\ \sf\longmapsto Density=2g/ml$

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3 years ago

Selenium (Se) has 30 protons and 20 neutrons in each atom, therefore its atomic

allochka39001 [22]

Answer:

30, 50

Explanation:

Hello,

In this since an element's atomic number is equal to the number of protons in its atom, we can infer that selenium's atomic number is 30. Moreover, due to the fact the the neutrons are equal to the atomic mass minus the atomic number or the number of protons, by knowing the number of neutrons we compute the atomic as follows:

$neutrons=mass-protons\\\\mass=neutrons+protons\\\\mass=30+20\\\\mass=50a.m.u$

Thus, answer is 30, 50.

Best regards.

8 0

3 years ago

Explain why it is important that a chemical equation be balanced

skad [1K]

In order to follow the law of conservation of mass, each side must contain an equal amount of each atom

6 0

4 years ago

A homogeneous mixture is also called _______________. a solution. an element. a pure substance. a heterogeneous mixture. a compo

inessss [21]

A solution is right answer.

6 0

4 years ago

Consider a general reaction A ( aq ) enzyme ⇌ B ( aq ) A(aq)⇌enzymeB(aq) The Δ G ° ′ ΔG°′ of the reaction is − 5.980 kJ ⋅ mol −

Grace [21]

Answer : The value of $K_{eq}$ is, 11.2

The value of $\Delta G_{rxn}$ is -9.04 kJ/mol

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

$\Delta G^o=-RT\times \ln K_{eq}$

where,

$\Delta G^o$ = standard Gibbs free energy = -5.980 kJ/mol = -5980 J/mol

R = gas constant = 8.314 J/K.mol

T = temperature = $25^oC=273+25=298K$

$K_{eq}$ = equilibrium constant = ?

Now put all the given values in the above formula, we get:

$\Delta G^o=-RT\times \ln K_{eq}$

$-5980J/mol=-(8.314J/K.mol)\times (298K)\times \ln K_{eq}$

$K_{eq}=11.2$

Thus, the value of $K_{eq}$ is, 11.2

Now we have to calculate the $\Delta G_{rxn}$ .

The formula used for $\Delta G_{rxn}$ is:

The given reaction is:

$A(aq)\rightleftharpoons B(aq)$

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$

$\Delta G_{rxn}=\Delta G^o+RT\ln \frac{[B]}{[A]}$ ............(1)

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction = ?

$\Delta G_^o$ = standard Gibbs free energy = -30.5 kJ/mol

R = gas constant = $8.314\times 10^{-3}kJ/mole.K$

T = temperature = $37.0^oC=273+37.0=310K$

Q = reaction quotient

[A] = concentration of A = 1.8 M

[B] = concentration of B = 0.55 M

Now put all the given values in the above formula 1, we get:

$\Delta G_{rxn}=(-5980J/mol)+[(8.314J/mole.K)\times (310K)\times \ln (\frac{0.55}{1.8})$

$\Delta G_{rxn}=-9035.75J/mol=-9.04kJ/mol$

Therefore, the value of $\Delta G_{rxn}$ is -9.04 kJ/mol

3 0

3 years ago