CO₂ + H₂O -------> H₂CO₃
moles of CO₂ =
=
= 11.997 mol
mole ratio of CO₂ : H₂O = 1 : 1
∴ moles of H₂O = (`11.997 mol ) * 1
= 11.997 mol
≈ 12 mol
3
One from fe
And two from cl2
The major alkene product that results when n,n-dimethylhexan-2-amine undergoes cope elimination is hexene or hex-1-ene.
The reaction in which an amine is oxidize to an intermediate called an N-oxide which , when heated , acts as base in an intramolecular elimination reaction. The oxidation of tertiary amine into N-oxide is called cope reaction.
This elimination gives the less substituted alkene along with more substituted alkene which is Zaitsev product.
Example: Cope elimination of n,n-dimethylhexan-2-amine form hexene.
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Answer:
Explanation: since oxalic acid is a weak acid it wont provide a strong acidic medium. So in order to provide a strong acidic medium dilute sulphuric acid is added.