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3 years ago

What is the solution set for 2f ≤ 2?

Mathematics

1 answer:

Firlakuza [10]3 years ago

6 0

Answer:

f ≤ 1

Step-by-step explanation:

I hope this helps, I got a few people to help me and really only remembered the answer so sorry I can't teach you much but I have the answer

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Jayce goes out for a walk. He walks 5/4 miles from home. He walks back 1/2 mile before meeting up with his friend Macy. Write an

GarryVolchara [31]

$+ \frac{5}{4} - \frac{1}{2} = \frac{1}{4}$
Hope this helps. - M

3 0

3 years ago

In the statement “If a line is bisected then it is cut into two equal parts”. The hypothesis is “If a line is bisected” and the

tensa zangetsu [6.8K]

Answer:

True

Step-by-step explanation:

The hypothesis of a conditional statement is the "if" part. This means the hypothesis is "If a line is bisected."

The conclusion of a conditional statement is the "then" part. This means the conclusion is "then it is cut into two equal parts."

8 0

3 years ago

Read 2 more answers

What's the slope of line 2?

WARRIOR [948]

Answer:

Step-by-step explanation:

The slope of line 2= $\frac{-3-(-3)}{7-5}$

3 0

3 years ago

Read 2 more answers

Yeah I need some help yall

Fantom [35]

Answer:

the answer is written in the picture.

Step-by-step explanation:

7 0

3 years ago

Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced

Sati [7]

Answer:

$\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\$

$W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}$

Step-by-step explanation:

$\text{If an urn contains two blue balls} (denoted \:B_1 \:and \:B_2) \text{and three white balls}$ , $(denoted \:W_1, W_2, \:and\: W_3)$

If One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and its color is recorded.

The 25 Possible outcomes of this experiment are listed below:

$\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\$

$W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}$

The tree diagram of this event is also attached.

6 0

3 years ago