The fare of $(20 - 2.5) = $17.5 will maximize the total fare.
<h3>What is Differentiation?</h3>
Differentiation means the rate of change of one quantity with respect to another. The speed is calculated as the rate of change of distance with respect to time.
Here, The operator for a round-trip fare of $20, carries an average of 500 people per day.
It is estimated that 20 fewer people will take the trip, for each $1 increase in fare.
for $x increase in fare, 20x less people will take the trip and at that time the total fare F is given by
f(x) =(20 + x)(500 - 20x)
f (x) = 10000 + 100x - 20x²
For f(x) to be maximum, the condition is dy/dx = 0
100 - 40x = 0
⇒ x = 2.5
Thus, the fare of $(20 - 2.5) = $17.5 will maximize the total fare.
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Indefinitely many solutions is the answer to this problem. All real numbers are solutions. The answer was 0=0.
You would be subtracting by 5 so the next three would be -16, -21, -26
Answer: the answer would be 4.5
Step-by-step explanation:
she walks 3 miles every 80 minutes and 80 plus 80 would be 160 but this is 120 so it would be 80 plus 40 so its half of 80 so half of 3 is 1.5 so there, hopes this helps
