If the roots to such a polynomial are 2 and

, then we can write it as

courtesy of the fundamental theorem of algebra. Now expanding yields

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.
So this makes me think you're expected to increase the multiplicity of one of the given roots, or you're expected to pull another root out of thin air. Judging by the choices, I think it's the latter, and that you're somehow supposed to know to use

as a root. In this case, that would make our polynomial

so that the answer is (probably) the third choice.
Whoever originally wrote this question should reevaluate their word choice...
Answer:
Step-by-step explanation:
6 is the thousands place
0 (right next to it) is the 10 thousands place
9 is the hundred thousands place. There is only 1 nine present so the answer is unique.
Answer:
x38
Step-by-step explanation:
Answer: 1/3
<u>Divide</u>
30/90÷30/30=1/3
Since we are simplifying fractions we divide the numerator and the denominator by a number the fraction can go into.
We could use 10 then divide by 3. You can also just divide by 30 and get the answer.
Let's try dividing by 10 then 3!
30/90÷10/10=3/9
3/9÷3/3=1/3
As you can see we still get 1/3 when we divide by 3. Even tho you have to divide twice you still get 1/3. That's all that matters.
276 divides by 4 = 69
So 3x69 = 207 + 276 = $483