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3 years ago

A number line going from 0 to 3 in increments of 3.

Mathematics

2 answers:

Alexandra [31]3 years ago

6 0

Answer:

Step-by-step explanation:

did it on edge

butalik [34]3 years ago

3 0

Answer:

2 divided by 1/2 is 4.

Step-by-step explanation:

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Is 3/8 estimated to be closer to 0 or 1?

kolezko [41]

The cut-off point is 0.5: higher than this would be closer to 1, and lower would be closer to 0

and 3/8 is lower than 0.5: we know this because a bigger number, 4/8 is equal to 0.5

so it's closer to 0!

3 0

3 years ago

Read 2 more answers

A first number plus twice a second number is 9. Twice the first number plus the second totals 27. Find the numbers

SOVA2 [1]

Create a a system of 2 equations: 2x + y = 27 and 2y + x = 9, with x being the first number and y being the second. solve for the two variables and you'll get the first number is 15 and the second is -3.

6 0

3 years ago

Blank divided by blank equals 6 what is the two blanks

Travka [436]

36 by 6 blah blah blah

4 0

2 years ago

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Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

A cylinder is sliced by a plane that is not parallel to the base and intersects only the lateral surface. the resulting cross se

Oxana [17]

The cylinder that is sliced by the plane which is not parallel to the base of the cylinder and intersects only at the lateral surface is called an ellipse.

<h3>What is the formation of an Ellipse in a Cylinder?</h3>

When a cylinder with a longitudinal axis (z) is sliced at an angle to the xy plane, an elliptical shape is created.

In a circle, every plane crosses a circular cylinder perpendicularly to its axis. A plane that is neither at right angles to the axis nor parallel to it, crosses the cylinder in an elliptical shape.

Learn more about an ellipse here:

brainly.com/question/26679189

4 0

1 year ago

Read 2 more answers