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Kisachek [45]
2 years ago
11

Can someone try to help me and explain it for me

Mathematics
2 answers:
Alla [95]2 years ago
6 0

Answer:

g(f(0)) = 5

Step-by-step explanation:

To evaluate g(f(0)), evaluate f(0) then substitute this value into g(x)

From the table

when x = 0, then f(0) = 1

Then

g(1)

when x = 1 , then g(x) = 5

Thus

g(f(0)) = 5

scZoUnD [109]2 years ago
4 0

Answer:

5

Step-by-step explanation:

So first u look at what f(0) is. In the chart it says it is one. So then u look at what g(1) is and it says 5.

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RSB [31]

Answer:

-5

Step-by-step explanation:

“x” would be multiplication, right?

5 0
2 years ago
Which is the simplified form of the expression?
Anon25 [30]

Given:

Consider the given expression is:

10n-\dfrac{1}{3}(9n-12)

To find:

The simplified form of the given expression.

Solution:

We have,

10n-\dfrac{1}{3}(9n-12)

Using distributive property, it can be written as:

=10n-\dfrac{1}{3}(9n)-\dfrac{1}{3}(-12)

=10n-3n+4

=7n+4

Therefore, the correct option is A.

4 0
3 years ago
Mary has 3 red marbles and 7 yellow marbles in a bag. What is the probability of she draw 3 marbles at the same time, all of the
LenaWriter [7]
The probability would be 3/10 or 30%
3 0
3 years ago
A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
2 years ago
What the simplest form for 5 4/32?
stira [4]
Ok so the answer is 160/32
4 0
2 years ago
Read 2 more answers
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