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2 years ago

Please help me with this!!!!

Mathematics

1 answer:

Ket [755]2 years ago

4 0

Answer:

mean: 4

median: 5

mode: 5

Step-by-step explanation:

Hi there!

Let's first start with the mean

the mean is the average of all of the numbers; we add up how many hours each week each student spent playing video games and then divide it by how many people responded (9)

(0+5+7+5+3+0+9+5+2)/9

add all of the numbers on top

36/9

divide

the mean is 4

now find the median, or the value that separates the upper half from the lower half of the data (it's the "center" value).

first, list the numbers in order from least to greatest

0,0,2,3,5,5,5,7,9

now get rid of the largest number and the smallest number (0 and 9)

the set is now:

0,2,3,5,5,5,7

now get rid of the largest and smallest number in the new set (0 and 2)

the set becomes:

2,3,5,5,5

get rid of the largest and smallest number in the new set (2 and 5)

3,5,5

get rid of the largest and smallest number in the new set (3 and 5)

the median is therefore 5

the mode is the number that occurs most frequently in the data set

here's our list again of all of the numbers from least to greatest:

0,0,2,3,5,5,5,7,9

we can count how many times each number appears to find the mode

0: 2 times

2: 1 time

3: 1 time

5: 3 times

7: 1 time

9: 1 time

since 5 appeared the most times, then the mode is 5

hope this helps!

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Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$

4 0

2 years ago

Compare 2.3 and 2.03

Andru [333]

2.3= 2.03 so there for it is equal

8 0

3 years ago

(x,-2) and (-9,1);slope: -3

amid [387]

Answer:

x= -10

Step-by-step explanation:

The equation is y2-y1 over x2 over x1 so

1-(-2) over -9-(x)=3

1+2=3 over -9-(x)

3/-9-x times -9-x = 3 times -9-x

3=3(-9-x)

3=-27-3x

3+27=-3x

30= -3x

-10= 3x

hope it helps man!!! :)

ps may i have brainliest so i can level up

6 0

3 years ago

Which of the following best describe(s) the diagonals of a rectangle. Select all that apply.

Evgesh-ka [11]

Answer:

I believe it is congruent and intersecting

Step-by-step explanation:

6 0

3 years ago

Find the greatest common factor of the following monomials: 20a3 and 8a2

dimulka [17.4K]

GCF of given monomials are $4a^2$

Solution:

Given that we have to find the greatest common factor

Given monomials are:

$20a^3 \text{ and } 8a^2$

When we find all the factors of two or more numbers, and some factors are the same, then the largest of those common factors is the Greatest Common Factor

Let us first find the GCF of 20 and 8 and then find GCF of variables and then multiply them together

GCF of 20 and 8:

The factors of 8 are: 1, 2, 4, 8

The factors of 20 are: 1, 2, 4, 5, 10, 20

Then the greatest common factor is 4

$GCF\ of\ a^3 \text{ and } a^2\\\\a^3 = a^2 \times a\\\\a^2 = a^2$