Question

What is the area of a rectangle with vertices (2, 3), (9, 3), (9, -2), and (2, -2)

Answer 1

I hope this helps you

Answer 2

Answer with explanation:

The Vertices of Rectangle are,A (2, 3), B(9, 3), C(9, -2), and D(2, -2).

Area of Rectangle = Length × Breadth

$\text{Use Distance formula to find distance between two points}=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}}\\\\\text{Length}=\sqrt{(9-2)^2+(3-3)^2}=\sqrt{7^2}=7\\\\\text{Breadth}=\sqrt{(9-9)^2+(-2-3)^2}=\sqrt{(-5)^2}=\sqrt{5^2}=5$

So, Area of Rectangle = 7 × 5

                      = 35 square units