Ok so first we find the equation that equals one variable.
2y = -x + 9
3x - 6y = -15
We solve for y.
2y = -x + 9
y = -x/2 + 9/2
Then we plug in this y value into the other equation to keep only one variable so we can solve for it.
3x - 6y = -15
3(-x + 9/2) - 6y = -15
-3x + 27/2 - 6y = -15
-9y + 27/2 = -15
-9y = 3/2
-y = 3/18
y = -3/18
Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.
y = -x/2 + 9/2
-3/18 = -x/2 + 9/2
-84/18 = -x/2
-x = 9 1/3
x = -28/3
Your answer would be (-28/3, -3/18)
Hope this helps!
Answer:
yes, the given relation is a function.
Step-by-step explanation:
The given relation is
{(–3, –2), (–1, 0), (1, 0), (5, –2)}
A relation is called function if each element of the domain is paired with exactly one element of the range.
It means for each value of x there exist a unique value of y.
In the given relation for each value of x there exist a unique value of y.
Therefore the required solution is yes and this relation is a function.
Is your question true or false?
2abc - 3ab = -30? if a =2, b = -3 and c= 4
plug in
2(2)(-3)(4) - 3(2)(-3) = -30
Simplify
-48 + 18 = -30
-30 = -30
Both sides are equal so
It's true.
Answer:
-3±√89/10
Step-by-step explanation:
