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4 years ago

Points that lie on the same line are called

Mathematics

2 answers:

butalik [34]4 years ago

6 0

Collinear <span>Points are points that land on the same line.

You see how in this image PQR's points all are on one line?
Thats a Collinear Point</span>

Misha Larkins [42]4 years ago

3 0

<span>Collinear points</span> are points that are on the same line

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a worker in a silver mine descends 71 feet. Use an integer to represent the change in the workers position.

alexira [117]

Answer:

iuyhgt

Step-by-step explanation:

6 0

3 years ago

What is the measure of AB

Papessa [141]

Check the picture below.

make sure your calculator is in Degree mode.

7 0

3 years ago

Find the indicated limit, if it exists.(7 points)

Alecsey [184]

Answer:

Step-by-step explanation:

The left hand limit is when we approach zero from left. We use the function on this domain in finding the limit.

$\lim_{x \to 0^-} f(x)=7-x^2$

$\lim_{x \to 0^-} f(x)=7-(0)^2=7$

The right hand limit is

$\lim_{x \to 0^+} f(x)=10x+7$

$\lim_{x \to 0^+} f(x)=10(0)+7=7$

Since the left hand limit equals the right hand limit;

$\lim_{x \to 0} f(x)=7$

7 0

3 years ago

4-member curling team is randomly chosen from 6 grade 11 students and 8 grade 12 students. What is the probability that the team

Ivanshal [37]

Answer:

0.5944 = 59.44% probability that the team has at least 2 grade 11 students

Step-by-step explanation:

The students are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

We have that:

6 + 8 = 14 students, which means that $N = 14$

6 grade 11 students means that $k = 6$

Teams of 4 members means that $n = 4$

What is the probability that the team has at least 2 grade 11 students?

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,14,4,6) = \frac{C_{6,0}*C_{8,4}}{C_{14,4}} = 0.0699$

$P(X = 1) = h(1,14,4,6) = \frac{C_{6,1}*C_{8,3}}{C_{14,4}} = 0.3357$

Then

$P(X < 2) = P(X = 0) + P(X = 1) = 0.0699 + 0.3357 = 0.4056$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.4056 = 0.5944$

0.5944 = 59.44% probability that the team has at least 2 grade 11 students

5 0

3 years ago

Write your answer in simplest radical form

pogonyaev

Answer:

a = sqrt(2)

Step-by-step explanation:

This is a right triangle so we can use trig functions

sin theta = opp / hyp

sin 30 = a / 2 sqrt(2)

2 sqrt(2) sin 30= a

2 sqrt(2) * 1/2 =a

sqrt(2) =a

8 0

3 years ago