Third inversion and second inversion
For the answer to the question above, let's start with the whole circle.
Let's assume that <span>the maximum possible area of a rectangle inscribed in a complete circle is achieved when the rectangle is a square.
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D= Circle's Diameter = 16
square's area = (D^2) / 2 = 256/2 =128
Imagine we want to break the circle into two semicircles, the square would be divided into two rectangles which would have the maximum possible area.
rectangle's area = square's area / 2 = 128/2 = 64
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