Answer:
well let’s break this down
Let’s make type a coffee “a”
And type b coffee “b”
a is 4.35
b is 5.70
We knwo that b is twice as many as a
The total is 614.25
So we can do soemthing like this
4.35a+ (5.70b)2 = 614.25
Now solve
If we simplify its really
4.35a+11.40b =614.25
I like multiply by a 100 to get rid of decimals
435a+1140b=61425
Here we can go 2 ways
We can isoalte a or b
im gonna isloate b
so it would be (61425-435a)/1140 =b
Now we can use that as a subsitube to find a
Now we can just do this
435a +1140(61425-435a)/1140 = 61425
Pop it through an algebra calculator (just search up math pa..Pa and copy paste it, edit if needed) and then you’d get your answer
Answer:
2
Step-by-step explanation:
2:3:9......added together = 14
2/14 (500) = 1000/14 = 71.43
3/14 (500) = 1500/14 = 107.14
9/14 (500) = 4500/14 = 321.43
Answer: a) An = An-1 + An-2
b) 55ways
Step-by-step explanation:
a) a nickel is 5 cents and a dime is 10cent so a multiple of 5 cents is the possible way to pay the tolls in both choices.
Let An represents the number of possible ways the driver can pay a toll of 5n cents, so that
An = 5n cents
Case 1: Using a nickel for payment which is 5 cents, the number of ways given as;
An-1 = 5( n-1)
Case 2: using a dime which is two 5 cents, the number of ways is given as;
An-2 = 5(n-2)
Summing up the number of ways, we have
An = An-1 + An-2
From the relation,
If n= 0, Ao= 1
n =1, A1= 1
b) 45 cents paid in multiples of 5cents will give us 9 ways(A9)
From the relation, we have that
Ao = 1
A1 = 1
An =An-1 + An-2
Ao = 1
A1 = 1
A2 = A1+Ao = 1+1= 2
A3 = A2 + A1 = 3
A4 = A3+A2=5
A5=A4+A3=8
A6=A5+A4=13
A7 =A6+A5 = 21
A8= A7+A6= 34
A9= A8+A7= 55
So there are 55ways to pay 45cents.
