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ra1l [238]
3 years ago
12

Math problem 10 points

Mathematics
1 answer:
Svetach [21]3 years ago
3 0
(a) 24

(b) 0.037 ft^3

(c) 0.888
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Dave rented a limousine for his wife's birthday. The hourly rate is $70. They used the limousine for 4 hours, plus Dave gave the
Alexxandr [17]
70x4=280
20% of 280 is 5.60
280+5.60=



285.60
6 0
3 years ago
Solve the system of equations -x+6y=2 and -3x+y=-11 by combining the equations.
Arada [10]
X=4,,,,,,,,,,,,,,,,,,,,,,,,,,y=1,,,,,,,,,
Combine (5-i)+3i
3 0
3 years ago
2/5 ÷ 22/35 <br>simplify​
Sliva [168]

Answer:

7/11 (Simplified Already)

Step-by-step explanation: 25÷2235=?

Dividing two fractions is the same as multiplying the first fraction by the reciprocal (inverse) of the second fraction.

Take the reciprocal of the second fraction by flipping the numerator and denominator and changing the operation to multiplication. Then the equation becomes

25×3522=?

For fraction multiplication, multiply the numerators and then multiply the denominators to get

2×355×22=70110

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 70 and 110 using

GCF(70,110) = 10

70÷10110÷10=711

Therefore:

25÷2235=711

Solution by Formulas

Apply the fractions formula for division, to

25÷2235

and solve

2×355×22

=70110

Reduce by dividing both the numerator and denominator by the Greatest Common Factor GCF(70,110) = 10

70÷10110÷10=711

Therefore:

2/5÷22/35=7/11

6 0
4 years ago
Read 2 more answers
What is the LCM of 168 and 196.
romanna [79]

Answer:

1176

hope this will help you

7 0
3 years ago
Read 2 more answers
A pool measuring 10 meters by 26 meters is surrounded by a path of uniform​ width, as shown in the figure. If the area of the po
igomit [66]

Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.

<h3>How to find the width and length?</h3>

First, find the area of the pool:

= Length x Width

= 10 x 26

= 260 meters ²

The area of the path can therefore be found to be:

= Total area of pool and path combined - Area of pool

= 1,092 - 260

= 832 meters²

Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path

= √832

= 28.8

In conclusion, the width and length of the path are 28.8 meters.

Find out more on combined area at brainly.com/question/12966430

#SPJ1

8 0
1 year ago
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