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Dmitry_Shevchenko [17]
3 years ago
10

Draw a triangle with vertices (2,3), (3,5), and (5,3). Then translate 4 units left. Graph the translated figure and provide the

translated coordinates.​
Mathematics
1 answer:
Masja [62]3 years ago
7 0
(6,3)(7,5)(8,3)

(X,Y)
left/right = X
up/down = Y
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What is a number that is greater than 40 who is prime fact tour is a send contains three prime numbers that do not repeat
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4 years ago
How do you solve 7/12 ÷ 2 5/8
Darya [45]
First off, we'd convert the mixed fraction to "improper" and then proceed,

\bf \stackrel{mixed}{2\frac{5}{8}}\implies \cfrac{2\cdot 8+5}{8}\implies \stackrel{improper}{\cfrac{21}{8}}\\\\&#10;-------------------------------\\\\&#10;\cfrac{7}{12}\div \cfrac{21}{8}\implies \cfrac{7}{12}\cdot \cfrac{8}{21}\implies \cfrac{\underline{7}}{3\cdot \underline{4}}\cdot \cfrac{2\cdot \underline{4}}{3\cdot \underline{7}}\implies \cfrac{2}{9}
8 0
4 years ago
Read 2 more answers
A cookie recipe calls for ¾ cup of sugar. You have the
solniwko [45]

Answer:

1/2 cup and 2 1/8 of a cup

Step-by-step explanation:

1/8 +1/8=1/4

1/2 is equaled to 2/4

so 2/4+1/4=3/4

7 0
2 years ago
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The data represent the results for a test for a certain disease. Assume one individual from the group is randomly selected. Find
sertanlavr [38]

Answer:

The probability of getting someone who tests positive​, given that he or she had the disease is 0.8954.

Step-by-step explanation:

The data provided is:

                  YES        NO    Total

Positive      137           8      145

Negative     16          139    155

Total            153         147    300

An individual is selected at random from the group.

We need to compute the probability of getting someone who tests positive​, given that he or she had the disease.

The conditional probability of an event <em>A</em> given that another event <em>B</em> has already occurred is:

P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{n(A\cap B)}{n(B)}

Let <em>A</em> = individuals who tests positive and <em>B</em> = individual who had the disease.

The number of individuals who tests positive and had the disease is,

n (A ∩ B) = 137

n (B) = 153

Compute the conditional probability of A given B as follows:

P(A|B)=\frac{n(A\cap B)}{n(B)}

            =\frac{137}{153}

            =0.8954

Thus, the probability of getting someone who tests positive​, given that he or she had the disease is 0.8954.

8 0
3 years ago
PLEASE HELP ME!<br> -----------------------------------
Nitella [24]

For the 1st question, the answer is A) Distributive Property:


The reason why Step 1 is A) Distributive Property is because you're distributing 2 to the #'s that are in the parenthesis().


For the 2nd question, it's either A) Reflexive Property or C) Symmetric Property...



7 0
3 years ago
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