Answer:
Probability that the sample contains at least five Roman Catholics = 0.995 .
Step-by-step explanation:
We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.
The Binomial distribution probability is given by;
  P(X = r) =  for x = 0,1,2,3,.......
 for x = 0,1,2,3,.......
Here, n = number of trials which is 8 in our case
          r = no. of success which is at least 5 in our case
          p = probability of success which is probability of Roman Catholic of 
                  0.90 in our case 
So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) 
 =  
 
 = 56 *  + 28 *
 + 28 *  + 8 *
 + 8 *  + 1 *
 + 1 *  
 
 = 0.995
Therefore, probability that the sample contains at least five Roman Catholics is 0.995.