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Nana76 [90]
3 years ago
12

Hello please help i’ll give brainliest

Mathematics
2 answers:
jeyben [28]3 years ago
8 0

Answer: the answer is C

Sliva [168]3 years ago
5 0

Answer:

c the bin 60-69 contains the most data values

Step-by-step explanation:

I got u

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Please help and show work!!
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17.

x = -2 is not a solution of -1 < x < 5 because -2 < -1 (-1 < -2 < 5 FALSE).

18.

m = 5 is a solution of 5 ≤ m because 5 ≤ 5 ( 5 ≤ m → m ≥ 5 greater than 5 or equal 5, 5 is equal 5)

19.

k = 10 is not solution of 2k - 3 < 1 because:

put the value of k to the inequality:

2(10) - 3 < 1

20 - 3 < 1

17 < 1 FALSE

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3 years ago
Do these ratios form a proportion?<br> $42 per 33 customers<br> $28 per 22 customers<br> yes<br> no
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No I have to have a denomination
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3 years ago
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What’s the area of the rectangle in terms of x if the length is (x+8) and the width is (2x-1)?
WARRIOR [948]

Answer:

Step-by-step explanation:

A=LW\\ \\ A=(x+8)(2x-1)\\ \\ A=2x^2-x+16x-8\\ \\ A=2x^2+15x-8

5 0
3 years ago
assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra
Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

           r = number of success = at least 4

           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

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3 years ago
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Need help with using the graph to find the numbers

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