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RUDIKE [14]
3 years ago
12

Order of Operations

Mathematics
1 answer:
emmasim [6.3K]3 years ago
6 0

Given:

4 + 9 + 16 \div 4 - 8 -3 \times  5

To find:

The number of possible solutions, if the Order of Operations did not exist.

Solution:

We have,

4 + 9 + 16 \div 4 - 8 -3 \times  5

Now,

Case 1:

[4 + 9 + 16] \div [4 - 8 -(3 \times  5)]=29\div (4 - 8 -15)

4 + 9 + 16 \div  4 - 8 -(3 \times  5)=-\dfrac{29}{19}

Case 2:

[4 + 9 + 16] \div  (4 - 8 -3) \times  5=29\div  (-7\times 5)

4 + 9 + 16 \div  (4 - 8 -3) \times  5=-\dfrac{29}{35}

Case 3:

4 + 9 + (16 \div 4) - 8 -(3 \times  5)=4+9+4-8-15

4 + 9 + (16 \div 4) - 8 -(3 \times  5)=-6

Many more possibilities are there.

Therefore, there are more than 3 possible solutions.

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A rectangular piece of plastic has an area of 10 square millimeters and a perimeter of 22 millimeters. What are the dimensions o
storchak [24]
The piece of plastic have dinmensions of 1mm by 10mm
5 0
3 years ago
Which expression is equivalent to (2^3)^-5
Ostrovityanka [42]
Hi!

You didn't list the options, but I think I know the answer. Let me know if my answer isn't listed! :)

(x^{3} )^{-5}
We need to multiply the exponents.
3 · -5 = -15

The answer is 2^{-15}

Hope this helps! :)
3 0
3 years ago
Read 2 more answers
Help please:))
Blababa [14]

Answer:

a) Because this asks about the radius and height, I assume that we are talking about a cylinder shape.

Remember that for a cylinder of radius R and height H the volume is:

V = pi*R^2*H

And the surface will be:

S = 2*pi*R*H + pi*R^2

where pi = 3.14

Here we know that the volume is 1000cm^3, then:

1000cm^3 = pi*R^2*H

We can rewrite this as:

(1000cm^3)/pi = R^2*H

Now we can isolate H to get:

H = (1000cm^3)/(pi*R^2)

Replacing that in the surface equation, we get:

S = 2*pi*R*H + pi*R^2

S = 2*pi*R*(1000cm^3)/(pi*R^2) + pi*R^2

S = 2*(1000cm^3)/R + pi*R^2

So we want to minimize this.

Then we need to find the zeros of S'

S' = dS/dR = -(2000cm^3)/R^2 + 2*pi*R = 0

So we want to find R such that:

2*pi*R = (2000cm^3)/R^2

2*pi*R^3 = 2000cm^3

R^3 = (2000cm^3/2*3.14)

R = ∛(2000cm^3/2*3.14) = 6.83 cm

The radius that minimizes the surface is R = 6.83 cm

With the equation:

H = (1000cm^3)/(pi*R^2)

We can find the height:

H = (1000cm^3)/(3.14*(6.83 cm)^2) =  6.83 cm

(so the height is equal to the radius)

b) The surface equation is:

S = 2*pi*R*H + pi*R^2

replacing the values of H and R we get:

S = 2*3.14*(6.83 cm)*(6.83 cm) + 3.14*(6.83 cm)^2 = 439.43 cm^2

c) Because if we pack cylinders, there is a lot of space between the cylinders, so when you store it, there will be a lot of space that is not used and that can't be used for other things.

Similarly for transport problems, for that dead space, you would need more trucks to transport your ice cream packages.

3 0
2 years ago
. Osteen has 32 marbles in his collection. 18 of his marbles are red, four are blue, and the rest are
nalin [4]

Answer: B

Explanation:  

32 marbles in total.

18 red marbles

4 blue marbles

10 green marbles.

You are asked what part of Osteen's marbles are red?

Probability = number of possible outcomes/total number of out outcomes.

P(Red) = 18/32 = 9/16

Both, 18 and 32 are divisible by 2 which gives 9/16. Since 9/16 cannot be reduced any further, we live it as it is. If you wanted to plug this into a calculator that would give 0.5625 which is 56.25% of Osteen's marbles are red.

P(Blue) = 4/32 = 1/8. 1/8 = 0.125 which 12.5% of his marbles are blue.

P(Green) = 10/32 = 5/16. 5/16= 0.3125 which 31.25 of his marbles are green. When you add 0.5625 + 0.125 + 0.3125 = 1 which is 100%. All probabilities add up to 1.

Hope this elaborate explanation helps.

6 0
2 years ago
Warren has a container which holds 22 books of the same shape and size. The exact breakdown of his books is shown below:
ohaa [14]

Given:

Total number of book = 22

Number of white books = 6

Number of Purple books = 9

Number of green books = 7

To find:

The probability that Warren takes out a green book in both draws (with replacement).

Solution:

We know that,

\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

P(\text{White})=\dfrac{6}{22}

P(\text{Purple})=\dfrac{9}{22}

P(\text{green})=\dfrac{7}{22}

After replacement, the probability of event remains the same and the independent.

The probability that Warren takes out a green book in both draws is:

P=P(\text{green})\times P(\text{green})

P=\dfrac{7}{22}\times \dfrac{7}{22}

P=\dfrac{49}{484}

Therefore, the correct option is (a).

7 0
3 years ago
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