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kakasveta [241]
3 years ago
12

First to answer gets brainliest

Mathematics
1 answer:
Setler [38]3 years ago
4 0

Answer:

Your answer is A, or -200.

Since your slope is going down, you know that the number is going to be a negative value. Then, check where the line hits a direct point. You would notice that it hits every 200 number values, which means that your answer is A.

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Functions can be defined using graphs, tables, and ordered pairs. What is the domain of a function?
Agata [3.3K]

Step-by-step explanation:

the domain is all numbers

5 0
3 years ago
How is multiplication of two integers represented on a number line and a chip board?
labwork [276]
Can you give me an example? Thank you

8 0
3 years ago
2,10,18,26 find the 61st term
saw5 [17]

Answer:

482

Step-by-step explanation:

We can see that the numbers shown resemble an arithmetic sequence because they have a common difference. The formula for the nth term of an arithmetic sequence is:

a_{n} =a_{1} +(n-1)d

Where a_{1} is the first term, a_{n} is the nth term, and d is the common difference. To find the 61st term, all we need is the first term and the common difference. By looking at what given, we can say the first term is 2. Now, to find the common difference, we find the difference of a term from the term before it. In this case we can do 10-2, which is 8 , or the common difference. Since we have everything we need, it can be plugged into the equation:

a_{61} =2 + (61 - 1)*8\\a_{61} = 2 + 60*8\\a_{61} = 2 + 480\\a_{61} = 482

So, the 61st term is 482.

4 0
2 years ago
Order the values from least to greatest |2|, -3, |-5|, -1, 6
Burka [1]

Answer:

-1, -3, 2, 5, 6

Step-by-step explanation:

The numbers in the | | mean that it would be positive. Instead of being |-5|, it would be positive 5.

4 0
2 years ago
Find the average value of the function f(x)=−4sin(x) on the interval [π2,3π2] and determine a number c in this interval for whic
Ber [7]

Answer:

Step-by-step explanation:

The average value theorem sets:

if f (x) is continuous in [a, b] and derivable in (a, b) there is a c Є (a, b) such that

\frac{f(b)-f(a)}{b-a}=f'(c) , where

f(a)=f(π/2)=-4*sin(π/2) = -4*1= -4

f(b)=(3π/2)=-4*sin(3π/2) = -4*-1 = 4

\frac{4-(-4)}{(3\pi/2)-(\pi/2)}=f'(c)

\frac{8}{\pi }=f'(c)

f'(x)=-4cos(x) ⇒

f'(c)=-4cos(c)=\frac{8}{\pi }\\c=acos(\frac{-2}{\pi })\\

c≅130

8 0
3 years ago
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