The answer should be B tell me if I'm wrong.
Answer:
The answer to this question can be given as:
Method:
public static void showTwos(int number) //method definition.
{
method body.
System.out.print(number + " = "); //print number
while (number % 2 == 0) //condition
{
System.out.print("2 * "); //print message.
number = number / 2;
}
System.out.println(number); //print value.
}
Explanation:
In the above method definition firstly, we declare the method showTwos() that name is already given in the question then we pass a variable number as a parameter in the method. In this first, we take input number from the user and pass into this method. In this method we use a while loop it is an entry control loop in this loop first we modules the number if it is equal to 0.Then we divide the number by 2 and in the last, we print the value.
You'd want to look at the <span>glossary.</span>
Answer:
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Answer:
22
Explanation:
1. We are going to have at hand 32 Enqueue Operation, with 10 from front and 15 dequeue and 5 empty queue operation
2. You dequeued total number of 15-5 =10 elements since 5 dequeue did not change the state of the queue, so invariably 10 dequeue is done.
3. Next is to enqueued a total of 32 elements.
Enqueue Operation do not change the state(and Size) of the queue, and can be ignored.
4. To arrive at the Total Size of queue, we will have 32-10 = 22 at the end
Answer : 22 because its a 5 dequeue Operations.
