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Lena [83]
2 years ago
9

Which pdu is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model?.

Computers and Technology
1 answer:
yulyashka [42]2 years ago
5 0

The PDU that is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model is segment.

<h3>What is this PDU about?</h3>

Note that in the transport layer, a host computer is said to often de-encapsulate  what we call a segment so that they can be able to put back data to an acceptable or given format through the use of the application layer protocol that belongs to the TCP/IP model.

Therefore, The PDU that is processed when a host computer is de-encapsulating a message at the transport layer of the tcp/ip model is segment as it is the right thing to do.

Learn more about host computer from

brainly.com/question/553980

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What term is used to record successful and unsuccessful access attempts
MArishka [77]
I think it is called an audit trail. 
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4 years ago
Alarm filtering may be based on combinations of frequency, similarity in attack signature, similarity in attack target, or other
dezoksy [38]

Answer: False

Explanation:

 The given statement is false, as the alarm filtering is the process of classifying the various type of IDPS alert in the system and it can be managed more efficiently.

The IDPS administrator can easily set an alarm filtering in the running system. It can generate the various types of positive tract in the system and then adjust the different alarm classifications. Alarm filters are same as the packet filter in which they can easily filter the items from the source and destination IP address.

3 0
3 years ago
Develop an algorithm and write a C++ program that finds the number of occurrences of a specified character in the string; make s
nirvana33 [79]

Answer:

The algorithm is as follows:

1. Input sentence

2. Input character

3. Length = len(sentence)

4. count = 0

5. For i = 0 to Length-1

 5.1 If sentence[i] == character

    5.1.1 count++

6. Print count

7. Stop

The program in C++ is as follows:

#include <iostream>

#include <string.h>

using namespace std;

int main(){

char str[100];   char chr;

cin.getline(str, 100);

cin>>chr;

int count = 0;

for (int i=0;i<strlen(str);i++){

 if (str[i] == chr){

  count++;} }

cout << count;

return 0;}

Explanation:

I will provide explanation for the c++ program. The explanation can also be extended to the algorithm

This declares the string and the character

char str[100];   char chr;

This gets input for the string variable

cin.getline(str, 100);

This gets input for the character variable

cin>>chr;

This initializes count to 0

int count = 0;

This iterates through the characters of the string

for (int i=0;i<strlen(str);i++){

If the current character equals the search character, count is incremented by 1

 if (str[i] == chr){  count++;} }

This prints the count

cout << count;

8 0
3 years ago
How many centimeters are there in 1 meters
konstantin123 [22]
1 meters is = 100 centimeters
8 0
4 years ago
Read 2 more answers
Write a program that: Takes the list lotsOfNumbers and uses a loop to find the sum of all of the odd numbers in the list (hint:
Alika [10]

Answer:

Following are the code to this question:

#include <iostream>//defining header file

using namespace std;

int main()//defining main method

{

int x[]={2,3,4,6,7,8,9,1,11,12};//defining 1-D array and assign value

int i,sum=0;//defining integer variable

for(i=0;i<10;i++)//defining loop for count value

{

   if(x[i]%2==1)//defining if block to check odd value

   {

       sum=sum+x[i];//add value in sum variable

   }

}

cout<<sum;//print sum

return 0;

}

Output:

31

Explanation:

In the above-given program, an integer array "x" is declared that holds some integer values, and in the next line two integer variable "i and sum" is defined which is used to calculate the value.

In the next line, a for loop is declared, that counts all array value, and it uses the if block to check the odd value and add all the value into the sum variable.

5 0
3 years ago
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