Step-by-step explanation:
5.) This is an example of the Subtraction Property of Equality.
6.) This is an example of the Division Property of Equality.
7.) This is an example of the Addition Property of Equality.
Answer:
(C), Stratified.
Step-by-step explanation:
Stratified random sampling is a type of sampling procedure used for a heterogeneous population. The heterogeneous population is divided into strata before collecting the sample in case of stratified sampling.
Here, stratified random sampling is being done.
Hence, the correct option is (C), Stratified.
5 to 8 right or there more
Answer:
(6, -8)
Step-by-step explanation:
Solve this system by substitution: substitute (1/3)x - 10 for y in the second equation, obtaining:
2x + (1/3)x - 10 = 4, or (after multiplying both sides by 3):
6x + x = 42, or 7x = 42.
Then x = 6. Substituting this into the first equation, we get:
y = (1/3)(6) - 10 = -8
The solution is (6, -8)
Answer:
The mass of element after decay at the rate of 28.6% is 2.2 grams
Step-by-step explanation:
Given as :
The mass of element = 490 grams
The decay rate is 28.6 % per minute
The time period = 16 minutes
Let The mass of element after decay = m
Now,
The mass after T minutes = Initial mass of element × ![(1-\frac{Rate}{100})^{T}](https://tex.z-dn.net/?f=%281-%5Cfrac%7BRate%7D%7B100%7D%29%5E%7BT%7D)
The mass after T minutes = 490 grams × ![(1-\frac{28.6}{100})^{16}](https://tex.z-dn.net/?f=%281-%5Cfrac%7B28.6%7D%7B100%7D%29%5E%7B16%7D)
Or, The mass after T minutes = 490 grams × 4.562 × ![10^{-3}](https://tex.z-dn.net/?f=10%5E%7B-3%7D)
Or, The mass after T minutes = 2.235 grams
Hence The mass of element after decay at the rate of 28.6% is 2.2 grams Answer