Answer: weight of elephant has smaller percent error.
Step-by-step explanation:
Percent error = ![\dfrac{|\text{estimated value -actual value}|}{\text{actual value}}]\times100](https://tex.z-dn.net/?f=%5Cdfrac%7B%7C%5Ctext%7Bestimated%20value%20-actual%20value%7D%7C%7D%7B%5Ctext%7Bactual%20value%7D%7D%5D%5Ctimes100)
Estimated weight of elephant = 10,000 pounds
Actual weight of elephant = 12,400 pounds
Percent error of weight = 
Estimated weight of hippopotamus = 2,500 pounds
Actual weight of hippopotamus = 3,600 pounds
Percent error of weight = 
Since 19.35 < 30.55
hence, weight of elephant has smaller percent error.
Answer:
Step-by-step explanation:
In the past, mean of age of employees
i.e. 
Recently sample was taken
n = sample size = 60
Mean of sample = 45
Std dev of sample s = 16

(Right tailed test)
Since only population std deviation is known we can use t test only
Std error = 
Mean difference = 45-40 =5
Test statistic t=
df = 60
p value =0.008739
Since p < 0.05 we reject null hypothesis
The mean age has increased.
First you do the top
8n+3n-7=8*2+3*2-7=16+6-7= 22-7=15
Then you found out the bottom
6*2n-3(n-1)=6*2*2-3(2-1)=6*2*2-3*1=6*4-3*1=24-3*1=24-3=21
15/21 is your answer.
Hope this helps! :)
Let x be the original position.
After the first play they gain 9 yards. The position can be represented by
x + 9
After the second play they lose 22 yards. The position can be represented by
x + 9 - 22 = x - 13
Therefore, in total they lost 13 yards.