Answer:
2x, (x-2), (x+6)
Step-by-step explanation:
I just took the quiz on plato and I got it correct
P.S Can you guys give me the brainliest please
(x - 2)^2 will always be positive and will have a minimum value of 0
so f(x) will have minimum of 2
Range is [2,∞)
Answer:
<h3>
f(x) = - ⁴/₉(x - 3)² + 6</h3>
Step-by-step explanation:
The vertex form of the equation of the parabola with vertex (h, k) is:
f(x) = a(x - h)² + k
So for vertex (3, 6) it will be:
f(x) = a(x - 3)² + 6
<u>y intercept: 2</u> means f(0) = 2
f(0) = a(0 - 3)² + 6
2 = a(-3)² + 6
2 -6 = 9a + 6 -6
-4 = 9a
a = ⁻⁴/₉
Therefore:
The vertex form of quardatic function with vertex: (3,6) and y intercept: 2 is
<u>f(x) = - ⁴/₉(x - 3)² + 6</u>
Answer:
There is no possible triangles
Step-by-step explanation:
\frac{\sin A}{a}=\frac{\sin B}{b}
a
sinA
=
b
sinB
From the reference sheet (reciprocal version).
\frac{\sin O}{58}=\frac{\sin 52}{13}
58
sinO
=
13
sin52
Plug in values.
\sin O=\frac{58\sin 52}{13}\approx 3.5157403
sinO=
13
58sin52
≈3.5157403O=\sin^{-1}(3.5157403)= \text{ERROR}
O=sin
−1
(3.5157403)=ERROR
Sine cannot be greater than 1.
{No Possible Triangles}
No Possible Triangles
{}
{}
Results in the most extreme 5% of possible outcomes
Hope this helps :)
