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2 years ago

Help me with this question plzzzz ignore it being marked

Mathematics

1 answer:

xz_007 [3.2K]2 years ago

4 0

Answer:

Step-by-step explanation:

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It is less than 300. The ones digit is four times the hundreds digit. The tens digit is five more than the hundreds digit. The s

tester [92]

Answer:

Step-by-step explanation:

let the numbers at unit,ten and hundred place be x,y,z respectively,then number=100z+10y+x

also x=4z

y=z+5

and x+y+z=17

4z+z+5+z=17

6z=17-5=12

z=2

y=2+5=7

x=2×4=8

number=100×2+10×7+8=278

3 0

2 years ago

A grab-bag contains 30 packages worth $.65 each, 10 packages $.60 cents each, and 15 packages worth $.30 each. What is the expec

Dennis_Churaev [7]

The answer would be 0.03.
What I did was 50/15 which would get me 0.0333333333333. But since money can only the cents can only have two numbers. So it would be 0.03 as the answer. So it’s the answer d.

3 0

2 years ago

What is the answer ?

maksim [4K]

Answer:

17,13,11

Step-by-step explanation:

6 0

2 years ago

Help me pls I really really need help with this I'm so bad at math

MAVERICK [17]

Question 7: Answer J (7/8 - 1/2 = 3/8)

6 0

3 years ago

Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer

Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

$0=(3x+2)(x-4)$

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

$(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}$

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply $(3x+2)(x-4)$ i.e. $3x^2-12x+2x-8$ = $3x^2-10x-8$

So, the equation becomes:

$0=3x^2-10x-8$

Comparing this equation to standard quadratic equation:

$ax^2+bx+c=0$

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}$

The answer is same from both the approaches.

So, the correct answer is:

C) Both

3 0

2 years ago