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3 years ago

12

A person on a moving sidewalk travels 56 feet in 8 seconds. The moving sidewalk has a length of 210 feet. How long will it take

to move from one end to the other?
PLEASE HELP ME WILL REPORT IF TROLL

1 answer:

Klio2033 [76]3 years ago

3 0

Answer:

The answer is 1470 seconds.

Step-by-step explanation:

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Calcular: E = (sec245o + tg45o) ctg37o - 2cos60o

Vlada [557]

Answer:

$-2.813$

Step-by-step explanation:

Se simplifica inicialmente la fórmula en términos de las funciones trigonométricas fundamentales (Initially, the formula is simplified in terms of fundamental trigonometric functions):

$(\sec 245^{\circ} + \tan 45^{\circ} )\cdot \cot 37^{\circ} - 2\cos 60^{\circ}$

$\left(\frac{1}{\cos 245^{\circ}}+\frac{\sin 45^{\circ}}{\cos 45^{\circ}} \right)\cdot \left(\frac{\cos 37^{\circ}}{\sin 37^{\circ}} \right) - 2\cdot \cos 60^{\circ}$

$(-2.366 + 1 )\cdot (1.327) - 1$

$-2.813$

7 0

3 years ago

In what time will the interest on $960 amount to $61.20 at 8.5% per annum?

MrRa [10]

Answer:

$525 dollars

Step-by-step explanation:

5 0

2 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

<em>Number of projects in the first year = 90</em>

<em></em>

<em>b) </em>

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

2 years ago

On a scale drawing, a school is 1.6 feet tall. the scale factor is 1/22. Find the height of the school

Pie

Answer:

35.2 ft

Step-by-step explanation:

Multiply the scale factor and the height.

6 0

3 years ago

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Find the volume 15m 16m 16m 16m the picture is below please help

kolezko [41]

Answer:

5,376 m³

Step-by-step explanation:

cube - 16x16x16=4096

pyramid = 16x16x15/3=1280

4096+1280=5376

3 0

2 years ago