Answer:
Let's begin by writing the mathematical equations given by the sentences.
Let X = smaller number
Let Y = larger number
The first sentence tells us
X + Y = 38
The second sentence tells us
X = Y/3 + 6
Since you weren't given a specific method to use, you can use either the substitution method or the elimination(addition) method, whichever works best for you.
Since the 2nd equation has the X isolated, I'm going to isolate the X in the first equation,
X = 38 - Y
Since both equations are equal to X, I can set them equal to one another and solve for Y.
Y/3 + 6 = 38 - Y
Y + 18 = 114 - 3Y
4Y = 96
Y = 24
Then use either of the two original equations to solve for X
X + Y = 38
X + 24 = 38
X = 14
Step-by-step explanation:
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Answer:
Take the numbers 50 and 30. Their greatest common factor is 10, since 10 is the greatest factor that both numbers have in common. To find the GCF of greater numbers, you can factor each number to find their prime factors, identify the prime factors they have in common, and then multiply those together.
Step-by-step explanation:
Answer:
Step-by-step explanation:
5.2
Giovanni purchased 20 adult tickets and 5 child's tickets.
Step-by-step explanation:
Let,
x = Adult tickets
y = Child's tickets
According to given statement;
x+y=25 Eqn 1
One adult ticket costs $14 and one child ticket costs $8, therefore,
14x+8y=320 Eqn 2

Putting value of x in Eqn 1;

Giovanni purchased 20 adult tickets and 5 child's tickets.
Keywords: Linear equations, Addition
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Answer:
log[(c^y)/(r^8)] this is m your answer