Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,
![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)
meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
JK where T is the midpoint. J >>>>> T >>>>> K.
JK = 5x - 3
JT = 2x + 1
Because T is the midpoint, it means that JT = TK
So, JT + TK = JK
(2x + 1) + (2x + 1) = 5x - 3
4x + 2 = 5x - 3
4x - 5x = -3 - 2
-x = -5
x = 5
JK = 5x - 3
JK = 5(5) - 3
JK = 25 -3
JK = 22
The length of JK is 22.
Answer is B. 3
2/3 x 3 = 6/3 = 2 cups
The numerical factor<span> of a </span>multiplication expression like 3x<span> is calied a coefficient</span>
Hola! Intente resolverlo pero solo hice la primera por mi tiempo ahorita mismo y era:
f(0)=1
Toda la ecuación
