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yuradex [85]
3 years ago
7

What is the coordinate for the image of point H(2, –6) under a 90° clockwise rotation about the origin? H’(–6, –2) H’(6, –2) H’(

–6, 2) H’(6, 2)
Mathematics
2 answers:
Igoryamba3 years ago
9 0

Answer:

The answer is H'(-6,-2).

Hope this helps!

FinnZ [79.3K]3 years ago
3 0
H'(-6,-2), because the point starts in quadrant 4 and a 90 degree shift clockwise will take it to the third quadrant and H'(-6, -2) is the only point in quadrant 3
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Here is your answer:

Step-by-step explanation:

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3 years ago
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What is 75 minutes to ten hours in ratio and simplest form
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1:8

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7 0
2 years ago
Slope-Intercept Form
vovikov84 [41]

Answer:

y = -2x + 3

Step-by-step explanation:

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Solve the following simultaneous linear equations.<br>2x + y = 5<br>4x – 3y = -10​
Jet001 [13]

Answer:

(1/2,4)

Step-by-step explanation:

First, determine y in first equation: 2x+y=5 or  y=5-2x

replace value of y determined in first equation (5-2x) into 2nd equation    

4x-3(5-2x)=-10

4x-15+6x=10

10x=5

x=1/2

put value of x into either equation to solve for y so

2(1/2)+y=5

1+y=5

y=4

answer: x=1/2, y=4

check answer by substituting x and y into either equation:

4x-3y=-10

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or

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7 0
3 years ago
Is perpendicular to ? Explain.
olga2289 [7]
Two lines are perpendicular if and only if the product of their slopes is - 1.

So, you just need to find the slope of each line and find out the product of their slopes.

I will do one example for you.

L1: y = 3x + 5

L2: y = - 3x + 14

L3: y = -x/3 + 14

The slope of a line is the coefficient of the x.

So the slopes are:

L1: slope 3
L2: slope -3
L3: slope -1/3

So now multiply the slopes of each pair of lines:

L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular

L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular

L1 and L3: (3) *  (-1/3) = -1 => Yes, they are penpendicular.
6 0
3 years ago
Read 2 more answers
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