Question

What is the coordinate for the image of point H(2, –6) under a 90° clockwise rotation about the origin? H’(–6, –2) H’(6, –2) H’(–6, 2) H’(6, 2)

Answer 1

Answer:

The answer is H'(-6,-2).

Hope this helps!

Answer 2

H'(-6,-2), because the point starts in quadrant 4 and a 90 degree shift clockwise will take it to the third quadrant and H'(-6, -2) is the only point in quadrant 3