What is the coordinate for the image of point H(2, –6) under a 90° clockwise rotation about the origin? H’(–6, –2) H’(6, –2) H’( –6, 2) H’(6, 2)
2 answers:
Answer:
The answer is H'(-6,-2).
Hope this helps!
H'(-6,-2), because the point starts in quadrant 4 and a 90 degree shift clockwise will take it to the third quadrant and H'(-6, -2) is the only point in quadrant 3
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Answer: Each piece would be 1/4 or 25%
Step-by-step explanation:
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