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2 years ago

8

A store has clearance items that have been marked down by 60%. They are having a sale, advertising an additional 15% off clearan

ce items. What percent of the original price do you end up paying?

1 answer:

astra-53 [7]2 years ago

6 0

Answer: 34%

Step-by-step explanation:

Given

Price is marked down by 60% with an additional discount of 15% on the marked down price

Suppose x is the original price of the item

After marking down, it is

$\Rightarrow x-x\times 0.6=0.4x$

after additional discount it is

$\Rightarrow 0.4x(1-0.15)=0.4x\times 0.85=0.34x$

Effective discount on the item is

$\Rightarrow \dfrac{x-0.34x}{x}\times 100=66\%$

Thus, a person is paying $100-66=34\%$ of the original price

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Making coconut cookies. The recipe calls for 420 g of coconut and 120 g of sugar. Only has 252 g of coconut. How much sugar must

geniusboy [140]

Answer: 72 grams.

Step-by-step explanation:

Let be "s" the amount of sugar in grams that must be used for 252 grams of coconut to keep the same ratio of coconut to sugar.

Knowing that in the recipe for the coconut cookies, should be 420 grams of coconut and 120 grams of sugar, and you only have 252 grams of coconut, you can set up this proportion to find "s":

$\frac{420grams}{120grams}=\frac{252grams}{s}$

Now, you need to solve for "s":

$\frac{420grams}{120grams}=\frac{252grams}{s}\\\\s(\frac{420grams}{120grams})=252grams\\\\s=(252grams)(\frac{120grams}{420grams})\\\\s=72grams$

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3 years ago

7. A triangle has an area of 20 in². If the height of the

GenaCL600 [577]

Step-by-step explanation:

the area of a triangle is

baseline × height / 2

in our case

baseline × 5 / 2 = 20 in²

baseline × 5 = 40

baseline = 8 in

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2 years ago

Find the area of the square ABCD

icang [17]

Step-by-step explanation:

Area of Square ABCD = 10m * 10m = 100m².

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2 years ago

Read 2 more answers

I Need help! If you help me you'll get 10 points!!

natka813 [3]

To solve this problem you must apply the proccedure shown below:

1. You have that the number of innings are expressed as a mixed number in the exercise:

$102^{\frac{2}{3} }$

2. If you want to write it as a decimal, you can convert the fraction as a decimal by dividing the numerator by the denominator and then, you must add this to the whole number part:

$102+\frac{2}{3}=102+0.67=102.67$

The answer is: 102.67

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3 years ago

PLEASE HELP GUYS i am struggling so much, two questions

ankoles [38]

Answer: the equation of the standard parabola

1) $(y-6)^2 = 4 (x-1)$

The equation of the standard parabola

2) (x+5)^2 = 16(y-2)

Step-by-step explanation:

<u>Explanation </u>

<u>Parabola:-</u>

The set of points in a plane whose distance from a fixed point and a constant ratio to their corresponding perpendicular distance from a fixed straight line is a conic.

Let S be a fixed point and l be a fixed straight line from any point P,the perpendicular PM is drawn to the line 'l'

The locus of P such that $\frac{SP}{PM} = constant$
The fixed point 'S' is called the Focus.
The fixed line'l 'is called the directrix of the conic
The constant ratio is known as the eccentricity, denoted by 'e'
If e=1 , the conic is called a parabola

1) <u> Step 1</u> :-

Given the focus S = (2,6) and directrix is x=0

we know that $\frac{SP}{PM}=1$

now cross multiplication , we get

$SP = PM$

squaring on both sides,we get

$SP^{2} = PM^2$

step 2:-

now using distance formula is

$\sqrt(((x_{2}-x_{1})^2+(y_{2} -y_{1} )^2)$

Given S =(2,6) and P(x,y) be any point on parabola

$SP^2 = (x-2)^2+(y-6)^2$ ........(1)

Now using perpendicular distance formula

let P(x , y ) be any point on the parabola

$\frac{ax_{1}+by_{1}+c }{\sqrt{a^2+b^2} }$

Given the directrix is x =0 and P(x,y) be any point on parabola

$PM^2 = \frac{x^2}{\sqrt{1}^2 }$ ......(2)

equating equation(1) and equation (2), on simplification

we get $(x-2)^2+(y-6)^2 = x^2$ .....(3)

apply $(a-b)^2 = a^2+ b^2+2 ab$

now the equation (3) is

$(y-6)^2 = 4 x-4$

now the standard form of parabola is

$(y-k)^2 = 4 a(x-h)$

<u>Final answer</u>:-

$(y-6)^2 = 4 (x-1)$

2) <u> Explanation:-</u>

<u>step 1:</u>

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

here the given points of 'x'co- ordinates are equal

Therefore the axis AS is parallel to y- axis

now the standard equation of parabola

$(x-h)^2 = 4 a (y-k)$

now you have to find' a' value

Given vertex of a parabola is A(-5,2) and its focus is S(-5,6)

The distance of $AS = \sqrt{(-5-(-5)^2+(2-6)^2}$

on simplification we get a =4

<u>Final answe</u>r :-

the vertex (h,k) = (-5,2) and a=4

$(x-h)^2 = 4 a (y-k)$

The standard parabola is $(x+5)^2 = 16 (y-2)$

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3 years ago