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dem82 [27]
3 years ago
10

Please help. Is algebra. PLEASE HELP NO LINKS OR FILES. I don't want links.

Mathematics
1 answer:
inysia [295]3 years ago
3 0
It would be B! :) have a good day
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Is 2 a solution of 4x +12=4?
mojhsa [17]

Answer:

no

Step-by-step explanation:

4x +12 = 4

4(2) +12 =/= 4

8 +12 =/= 4

8 +12 = 20

(sorry if it doesn't make sense,I tried)

5 0
3 years ago
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-3 + 12x help plzzzzz
Ivahew [28]

Answer: X=1/4 or X=0.25

Step-by-step explanation:

-3+12x

Bring the 3 to the other side to isolate x

12x=3

Divide both sides by 12

x=0.25

8 0
3 years ago
Carefully and accurately sketch the polynomial. Be sure to label all zeroes, the y-intercept, and any minima or maxima. Use your
dimulka [17.4K]

The graph of the polynomial function is represented in the attached diagram.

1) Zeroes:

P(x)=0 when

  • x=0;
  • x=2;
  • x=-3/2.

2) y-intercept:

when x=0, then

P(0)=-0^2(0-2)(2\cdot 0+3)=0.

Thus, y-intercept is at point (0,0).

3) Minima and maxima points:

  • minima - (0,0);
  • maxima - (-1.05,3.03) and (1.43,6.83)

8 0
3 years ago
7.25 cm plus 7.2 cm plus 8cm equals what
alisha [4.7K]
There correct answer to that question is 22.45
7 0
4 years ago
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19. The marked price of an oven is 30% above its cost. In a sale, it is
yaroslaw [1]

a) Marked price: $884, Cost: $680

b) 2.5 %

Step-by-step explanation:

a)

Let's call:

P = marked price of the oven

C = cost of the oven

We know that:

- The marked price of the oven is 30% above the cost, which means

P=(1+\frac{30}{100})C=1.30C (1)

- In the sale, the oven is sold at a discount of 25% on its marked price; so the price of the sale is (we call it S)

S=(1-\frac{25}{100})P=0.75P (2)

- We also know that the discount, which is the difference between the makerd price (P) and the discounted price (S) is

P-S=\$221 (3)

Substituting (2) into (3) we find marked price

P-0.75P=\$221\\0.25P=\$221\\P=\frac{221}{0.25}=\$884

Therefore, the cost of the oven is (from eq(1)):

C=\frac{P}{1.30}=\frac{884}{1.30}=\$680

b)

The percentage loss in this situation is given by the difference between cost of the oven and the final price at which the oven is sold.

In this case, we have:

C = $680 (cost of the oven)

The discounted prices is S, and can be f ound using eq(3):

S=P-221=884-221=\$663

Therefore, the oven costs 680$ but it is sold at 663$.

Therefore, we can calculate the percentage loss using the equation:

Loss=\frac{C-S}{C}\cdot 100 = \frac{680-663}{680}\cdot 100 =0.025\cdot 100 = 2.5\%

So, a percentage loss of 2.5%.

4 0
3 years ago
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