A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero.
t(x)=(x+5)^3+7
dt/dx=3(x+5)^2
d2t/dx2=6(x-5)
dt/dx=0 only when x=-5
However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.
So there is no turning point for this function.
Now in this problem, it is even easier than the above to show that there is no turning point. A turning point by definition is when the derivative or velocity changes sign. Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.
Answer:
y=(-9/5)x-3
Step-by-step explanation:
to find m:substitute -5 in x value,-3 in c value and 6 in y value in the equation y=mx+c.then,rewrite equation by substituting value of m and c
Answer:
6231
Step-by-step explanation:
Answer:
B.
Step-by-step explanation:
I'm not sure how to answer the 2. question
Answer:
Step-by-step explanation:
First you need to find the area then divide that by 14
