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Varvara68 [4.7K]
3 years ago
15

Is 2 a solution of 4x +12=4?

Mathematics
2 answers:
grin007 [14]3 years ago
8 0

Answer:

Step-by-step explanation:

mojhsa [17]3 years ago
5 0

Answer:

no

Step-by-step explanation:

4x +12 = 4

4(2) +12 =/= 4

8 +12 =/= 4

8 +12 = 20

(sorry if it doesn't make sense,I tried)

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In an airplane 35% of the passengers are children they’re 140 children on the airplane how many passengers are on the airplane
Angelina_Jolie [31]

Answer:

there are 49 passengers

Step-by-step explanation: 35%=0.35

0.35*140= 49


3 0
3 years ago
15:40:25 in simplest form
Contact [7]

Answer:

the answer is 3:8:5

Step-by-step explanation:

This is because it says Apple, coconut, and orange, but you put orange, apple, and coconut

3 0
3 years ago
It is estimated that there are 828 motor vehicles in the US it is estimated that there are 828 Motor vehicles in the US for ever
coldgirl [10]

Answer:

314 million

Step-by-step explanation:

Given that :

Number of motor vehicle in the U.S for every 1000 people = 828

If the number of motor vehicle in the United States = 260 million

Then,

Let x = number of people Given number of vehicles = 260,000,000

1000 people = 828 vehicles

x = 260,000,000

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8 0
3 years ago
Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ
MrRissso [65]

Answer:

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

Step-by-step explanation:

We get the limits of integration:

R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq  4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace

We use the spherical coordinates and  we calculate a triple integral:

V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4  \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}}  \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\

we get:

V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}

So,  the volume is:

\boxed{V=\frac{128\sqrt{2}\pi}{3}}

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