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zaharov [31]
3 years ago
5

Someone plzzzz help meee!!!!

Mathematics
1 answer:
Oxana [17]3 years ago
4 0
Find the tangent of the angle, using the height (472) minus the elevated height of the camera (2) which would be 470 meters, and also the distance away from the shuttle, which would be 750. Opposite divided by adjacent would make the tangent 0.626...so using a triangle chart, the closest whole numbered angle 0.626 would be to is 32 degrees.

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Question 20 points if correct
Vlada [557]

Answer:

B = 155° , C = 25° , D = 155°

Step-by-step explanation:

Given

A = 25°

C = A = 25° [ Vertically Opposite angles ]

Now

A + B = 180°( being linear pair)

25° + B = 180°

B = 180° - 25°

B = 155°

Also

D = B = 155°( vertically opposite angles )

5 0
4 years ago
Read 2 more answers
If sales tax is 6% and you buy a shirt for $25 how much do you owe?
Leona [35]

Answer:

26.50

Step-by-step explanation:

First we need to calculate the sales tax

25 * 6%

Changing to decimal from

25 * .06

1.50

Then we add the tax to the cost of the shirt

25+1.50

26.50

We owe 26.50

7 0
3 years ago
DG, EG, and FG are perpendicular bisectors of the sides of △ ABC . DG=5 centimeters and BD=12 centimeters.
IgorLugansk [536]
Hiya! The answer is 13. Trust me, I had this exact same question!

CG is 13 cm
5 0
3 years ago
Read 2 more answers
Find the solution to the differential equation<br><br> dB/dt+4B=20<br><br> with B(1)=30
natita [175]

Answer:

The solution of the differential equation is B=5+25e^{-4t+4}

Step-by-step explanation:

The differential equation \frac{dB}{dt}+4B=20 is a first order separable ordinary differential equation (ODE). We know this because a separable first-order ODE has the form:

y'(t)=g(t)\cdot h(y)

where <em>g(t)</em> and <em>h(y) </em>are given functions<em>. </em>

We can rewrite our differential equation in the form of a first-order separable ODE in this way:

\frac{dB}{dt}+4B=20\\\frac{dB}{dt}=20-4B\\\frac{dB}{dt}=4(5-B)\\\frac{1}{5-B}\frac{dB}{dt}=4

Integrating both sides

\frac{1}{5-B}\frac{dB}{dt}=4\\\frac{1}{5-B}\cdot dB=4\cdot dt\\\\\int\limits {\frac{1}{5-B}} \, dB=\int\limits {4} \, dt

The integral of left-side is:

\int\limits {\frac{1}{5-B}} \, dB\\\mathrm{Apply\:u-substitution:}\:u=5-B\\\int\limits {\frac{1}{5-B}} \, dB=\int\limits {\frac{1}{u}} \, dB\\\mathrm{du=-dB}\\-\int\limits {\frac{1}{u}} \,du\\\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)\\-\int\limits {\frac{1}{u}} \,du =-\ln \left|u\right|\\\mathrm{Substitute\:back}\:u=5-B\\-\ln \left|5-B\right|\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\-\ln \left|5-B\right|+C

The integral of right-side is:

\int\limits {4} \, dt = 4t + C

We can join the constants, and this is the implicit general solution

-\ln \left|5-B\right|+C=4t + C\\-\ln \left|5-B\right|=4t + D

If we want to find the explicit general solution of the differential equation

We isolate B

-\ln \left|5-B\right|=4t + D\\\ln \left|5-B\right|=-4t+D\\\left|5-B\right|=e^{-4t+D}

Recall the definition of |x|

|x|=\left \{ {{x, \:if \>x\geq \>0 } \atop {-x, \:if \>x0}} \right.

So

\left|5-B\right|=e^{-4t+D}\\5-B= \pm \:e^{-4t+D}\\B=5 \pm \:e^{-4t+D}\\B=5\pm \:e^{-4t}\cdot e^{D}\\B=5+Ae^{-4t}

where A=\pm e^{D}

Now B(1) =30 implies

B=5+Ae^{-4t}\\30=5+Ae^{-4}\\30-5=Ae^{-4}\\25e^{4}=A

And the solution is

B=5+(25e^{4})e^{-4t}\\B=5+25e^{-4t+4}

8 0
4 years ago
When Bart bought his car, it averaged 28 miles per gallon of gas. Now, the
velikii [3]

Answer:

14

Step-by-step explanation:

7 0
4 years ago
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