The remainder for 67 divided by 3 would be 1 because (this might be a bad explanation since i'm not good at explaining math without showing u my work) if u do divide 6 by 3, 3x2 is 6 and 6-6 is 0. Then if u divide 7 by 3, then 6 is the closest u can get to 7 without multiplying by a decimal. Then if u do 7-6, u get 1 and u cant divide 1 by 3 so the remainder would be 1.
Answer:
21
Step-by-step explanation:
To evaluate, substitute w = 6 into the expression, that is
15 + w = 15 + 6 = 21
Answer:
They are not commutative, because f(g(x)) and g(f(x) are not equal.
Step-by-step explanation:
In order for the composition of the functions to be commutative, we must have ...
f(g(x)) ≡ g(f(x))
for all values of x.
Here, we have f(g(x)) = 1 and g(f(x)) = 2. f(g(x)) and g(f(x)) are not equal, so the composition of the functions is not commutative.
just search it up on the internet
