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Rufina [12.5K]
3 years ago
7

Describe how you can tell whether a lines slope is greater than 1,equal to 1, or less than 1

Mathematics
1 answer:
Soloha48 [4]3 years ago
7 0

Answer:

Rise over Run

Step-by-step explanation:

You need to find the rise over run. Find a point where the line crosses a set of points on the graph. Then find another point on the graph where the line crosses. start at the bottom point and count up till you get even to where the point is. then count over till you get to the point. That is your rise over run. Now simplify the rise over run. You should get a number and that is how you can tell if if a lines slope is equal to 1, greater than 1, or less than 1.

Hope this Helps!

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Write an equation for the following: y varies directly with x and z. Find K when x=2, y=12 and z=5.
olga_2 [115]

\qquad \qquad \textit{direct joint variation} \\\\ \textit{\underline{y} varies directly with \underline{x} and \underline{z}}~\hspace{8.5em} \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}xz~\hfill } \\\\ \textit{\underline{y} varies directly with \underline{x}, }w^2\textit{ and }z^5~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}xw^2z^5~\hfill } \\\\[-0.35em] ~\dotfill

y = kxz\qquad \textit{we know that} \begin{cases} x=2\\ y=12\\ z=5 \end{cases}\implies 12=k(2)(5) \\\\\\ \cfrac{12}{(2)(5)}=k\implies \cfrac{6}{5}=k~\hspace{10em}\boxed{y=\cfrac{6}{5}xz}

6 0
2 years ago
Please help me out............................
Alina [70]

Answer:

<h2>b = 15°</h2>

Step-by-step explanation:

If Pq = RQ then ΔPQR is the isosceles triangle. The angles QPR and PRQ have the same measures.

We know: The sum of the measures of the angeles in the triangle is equal 180°. Therefore we have the equation:

m∠QPR + m∠PRQ + m∠RQP = 180°

We have

m∠QPR = m∠PRQ and m∠RQP = 60°

Therefore

2(m∠QPR) + 60° = 180°       <em>subtract 60° from both sides</em>

2(m∠QPR) = 120°           <em>divide both sides by 2</em>

m∠QPR = 60° and m∠PRQ = 60°

Therefore ΔPRQ is equaliteral.

ΔPSR is isosceles. Therefore ∠SPR and ∠PRS are congruent. Therefore

m∠SPR = m∠PRS

In ΔAPS we have:

m∠SPR + m∠PRS + m∠RSP = 180°

2(m∠SPR) + 90° = 180°            <em>subtract 90° from both sides</em>

2(m∠SPR) = 90°             <em>divide both sides by 2</em>

m∠SPR = 45° and m∠PRS = 45°

m∠PRQ = m∠PRS + b

Susbtitute:

60° = 45° + b           <em>subtract 45° from both sides</em>

15° = b

3 0
3 years ago
Write the quadratic equation whose roots are 2 and -4 and whose leading coefficient is 2
Goryan [66]

Answer:

2x^2+4x-16

Step-by-step explanation:

The quadratic can be written as

f(x) = a(x-z1)(x-z2) where z1 and z2 are the roots

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a is the leading coefficient

f(x) = 2(x-2)(x+4)

     = 2(x^2 -2x+4x-8)

     = 2(x^2 +2x-8)

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3 years ago
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Margarita [4]

Answer:

It comes down to what the equals sign means. It means,  that the two things mentioned on either side of the equation are the same thing. If you do something to the left side, you have presumably changed it.

Step-by-step explanation:

Hope this helps, If it did, then I would really appreciate it if you gave me Brainliest, I only need one more to rank up and it has taken forever to get to where I am currently. Thanks.

8 0
2 years ago
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A person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen he sells it at Rs 80 a pair find the gain p
k0ka [10]

Given,

CP of cosmetics = Rs 360 per dozen

SP of a pair of cosmetics = Rs 80

We need to find the profit percentage.

Solution,

We know that,

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SP of 1 cosmetic = 80/2 = Rs 40

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= Rs 40 - Rs 30

= Rs 10

Profit percentage is given by :

\%=\dfrac{profit}{CP}\times 100\\\\=\dfrac{10}{30}\times 100\\\\=33.34\%

So, the profit percentage is 33.34%.

7 0
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