Let 
be the 20 marks of the boys, and 
be the 10 marks of the girls.
We know that the global mean was 70, meaning that
Multiplying both sides by 30 we deduce that the sum of the scores of the whole classroom is
By the same logic, we work with the marks of the boys alone: we know the average:
And we deduce the sum of the marks for the boys:
Which implies that the sum of the marks of the girls is 
And finally, the mean for the girls alone is
Answer:
d) (179.20, 212.716)
Step-by-step explanation:
1000 : 345
569 : 195.96
Midpoint of (179.20, 212.716) is 195.958 which is the closest to 195.96
2y - 3x = 4
2y = 3x + 4
y = 3/2*x + 2
y = kx + b ==>
k = 3/2 = 1,5
A. 168 cm.
V=lwh
4 x 7 x 6 = 168 .
Answer:
3.14 cm²/min
Step-by-step explanation:
rate of increasing of radius, dr/dt = 0.01 cm/min
r = 50 cm
Area of plate, A = πr²
rate of increase of area
dA/dt = 2πr dr/dt
dA/dt = 2 x 3.14 x 50 x 0.01
dA/dt = 3.14 cm²/min
Thus, the increase of rate of area is 3.14 cm²/min.
