4 years ago

Find the area of a triangle with sides 8 equals 5 b equals 8 and C equals 11

Mathematics

1 answer:

IceJOKER [234]4 years ago

4 0

I round the answer to the second digit and get 18.33

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I neee help plss i have so lil time to hand it in

SashulF [63]

The Solution.

The given equation is

$\begin{gathered} y=|x|+7 \\ \text{Where x=11} \end{gathered}$

Substituting 11 for x, we can get the value of y.

$\begin{gathered} y=|11|+7 \\ y=11+7 \\ y=18 \end{gathered}$

Hence, the value of y is 18.

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Lisa [10]

Answer:

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Step-by-step explanation:

Given (AB )^T= B^T. A^T;

To prove this expression, we need to apply multiplication law, power law and division law of indices respectively, as shown below.

$(AB)^T = B^T.A^T\\\\Start, from \ Right \ hand \ side\\\\B^T.A^T = \frac{B^T.A^T}{A^T}.\frac{B^T.A^T}{B^T} (multiply \ through) \\\\ = \frac{A^{2T}.B^{2T}}{A^T.B^T} \\\\=\frac{(AB)^{2T}}{(AB)^T} \ \ (factor \ out \ the power)\\\\= (AB)^{2T-T} \ (apply \ division \ law \ of \ indices; \ \frac{x^a}{x^b} = x^{a-b})\\\\= (AB)^T \ (Proved)$

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3 years ago