Question

What is the sound level for a noise that has an intensity of 9.9 × 10-5 watts/m2?

Answer 1

we can use

sound level formula

$\beta=10log(\frac{I}{I_0} )dB$

where

$\beta$ is the sound level for a noise

I is intensity given

I0 is reference intensity

we know that reference intensity as

$I_0=1*10^{-12}W/m^2$

we are given

$I=9.9*10^{-5}W/m^2$

now, we can plug these values

and we get

$\beta=10log(\frac{9.9*10^{-5}W/m^2}{1*10^{-12}W/m^2} )dB$

now, we can simplify it

$\beta=10log(9.9*10^{-5+12} )dB$

$\beta=79.95635dB$................Answer