If the point `(3/5, 4/5)` corresponds to an angle θ in the unit circle, what is tan θ ?

attashe74 [19]

Problem 1

Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.

Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.

With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.

Refer to the diagram below.

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Problem 2

I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.

In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.

8 0

2 years ago

Please answer quickly I will give brainliest- Kelsey has a list of possible functions. Pick one of the g(x) functions below and

Marizza181 [45]

Answer:

1. Behavior

The g(x) is large and positive when x is large and positive;

The g(x) is large and negative when x is large and negative.

2. y-intercept= -18

3. The zeros are: -3, -2 and 3

Step-by-step explanation:

1. End behavior:

To find this you have to know the leading coefficient of the variable with the highest degree, and whether the degree is even or odd.

(x + 3) = x positive, coefficient 1

(x + 2) = x positive, coefficient 1

(x − 3)= x positive, coefficient 1

The coefficient is 1*1*1= 1 = positive

There are 3 x, so it will be x^3= odd

The behavior for odd and positive will be:

g(x) is + ∞ when x=>+∞

g(x) is -∞ when x=>-∞

or

The g(x) is large and positive when x is large and positive;

The g(x) is large and negative when x is large and negative.

2. Y-intercept

The y-intercept is the value of y when the graph touches the y-axis. The y-axis is located at x=0, so to find the y-intercept you need to put x=0 on the graph function. Some graphs can have two y-intercepts but the graph on the question only has one. The calculation will be:

y-intercept = g(0)= (0+3)(0+2)(0-3)

y-intercept = 3*2*-3

y-intercept= -18

3. Zeros

The zeros mean the value of x that will result as g(x) as zero. At this coordinate, the graph will touch the x-axis since g(0) is located on the x-axis. That is why this coordinate also called an x-intercept. The function is expressed as the product of three things. If any of them is 0, then the result will be 0. So we have 3 zeros

$x_{1}$ +3=0