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3 years ago

Which triangle is a right isosceles triangle?

Mathematics

1 answer:

Romashka [77]3 years ago

4 0

Answer:

A is the correct answer

Step-by-step explanation:

Hope that helps

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Please help me please will give brainliest

pshichka [43]

Answer:

Step-by-step explanation:

8 0

3 years ago

What is the equivalent decimal to this fraction? 10/45 0.2 0.222222222... 0.232323232323... 0.181818181818...

Ivan

Factorize the numerator and denominator, then simplify:

10/45 = (2×5)/(9×5) = 2/9

Now,

1/9 = 1/10 + 1/90

1/90 = 1/10 × 1/9 = 1/10 × (1/10 + 1/90) = 1/100 + 1/900

1/900 = 1/100 × 1/9 = 1/100 × (1/10 + 1/90) = 1/1000 + 1/9000

and so on, which is to say

1/9 = 1/10 + 1/100 + 1/1000 + …

1/9 = 0.111…

so that multiplying both sides by 2 gives

2/9 = 0.222…

5 0

2 years ago

Plz answer with explanation will choose brainliest

Mrrafil [7]

Answer:

The answer is A.

Step-by-step explanation:

When finding the distance, you have to subtract the two numbers and take the absolute the value of that difference.

3 0

3 years ago

What is (-8.1)-(-8.9)

polet [3.4K]

Answer:

0.8

Step-by-step explanation:

-8.1+8.9=0.8

so the answer is 0.8

5 0

2 years ago

Read 2 more answers

Tju [1.3M]

Answer:

Step-by-step explanation:

Rationalize the denominator of b. So, multiply the numerator and denominator by $\sqrt{x}$

$b = \frac{(1-2\sqrt{x}) *\sqrt{x}}{\sqrt{x}*\sqrt{x} }=\frac{1*\sqrt{x} -2\sqrt{x} *\sqrt{x} }{\sqrt{x} *\sqrt{x} }\\\\=\frac{\sqrt{x} -2x}{x}\\$

Now, find a +b

$a +b = \frac{2x+\sqrt{x} }{x}+\frac{\sqrt{x} -2x}{x}\\\\=\frac{2x+\sqrt{x} +\sqrt{x} -2x}{x}$

Combine like terms

$= \frac{2x-2x+\sqrt{x} +\sqrt{x} }{x}\\\\=\frac{2\sqrt{x} }{x}$

Now find (a + b)²

(a +b)² = $(\frac{2\sqrt{x} }{x})^{2}$

$= \frac{2^{2}*(\sqrt{x} )^{2}}{x^{2}}\\\\= \frac{4* x}{x^{2}}\\\\= \frac{4}{x}$

Hint: $\sqrt{x} *\sqrt{x} =\sqrt{x*x}=x$

5 0

2 years ago