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lara31 [8.8K]
3 years ago
8

45 POINTS* Find the values of x and y

Mathematics
1 answer:
OLEGan [10]3 years ago
8 0

Answer:

x =17 \sqrt{3}  \\ y = 34

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The perimeter of a stop sign has a perimeter of 16x2 - 80x. What is the length of one side?
uranmaximum [27]
Since a stop sign is an octagon it has eight sides.  So the perimeter will be:

p=8x,  p=perimeter and x=side length.  We are told that the perimeter is equal to:

16x^2-80x so we can say:

16x^2-80x=8x subtract 8x from both sides

16x^2-88x=0  factor out 8x

8x(2x-11), since we know x>0

x=11/2

x=5.5 units
7 0
3 years ago
Which theorem or postulate proves that △ABC and △DEF are similar?
yan [13]

Answer:

△ABC and △DEF are similar by SAS Similarity Theorem.

Option (C) is correct .

Step-by-step explanation:

Definition of SAS Similarity property

Two triangles are said to be similar by SAS Similarity property If two sides are proportional and one corresponding angle congruent .

In △ABC and △DEF

\frac{ED}{AB}= \frac{7}{21}

\frac{ED}{AB}= \frac{1}{3}

and

\frac{EF}{BC}= \frac{11}{33}

\frac{EF}{BC}= \frac{1}{3}

Thus

\frac{ED}{AB}=\frac{EF}{BC}= \frac{1}{3}

∠ABC = ∠DEF  (As given in the figure )

Thus △ABC and △DEF are similar by SAS Similarity property .

7 0
3 years ago
Read 2 more answers
Two congruent squares and a parallelogram were used to form the figure shown. 3 meters, 6 meters, 2.8 meters, 3 meters What is t
elixir [45]

The area of a figure is the amount of space the figure occupies

The surface area of the figure is 34.8 square meters

<h3>How to determine the area of the shape</h3>

From the question, we have:

  • The dimensions of the congruent squares are 3 m by 3 m
  • The dimensions of the parallelogram are height of 2.8 m, and base of 6 m

So, the area of the figure is:

Area = 2 * Area of square + Area of parallelogram

This gives

Area = 2 * (3m * 3m) + 2.8m * 6m

Evaluate the products

Area = 18m^2 + 16.8m^2

Evaluate the sum

Area = 34.8m^2

Hence, the surface area of the figure is 34.8 square meters

Read more about surface areas at:

brainly.com/question/24571594

3 0
2 years ago
A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground. which equation can be used to determine the
3241004551 [841]

Answer:

h(t)=-16t^2+85t+28  is equation of height of rocket.

Option D is correct.

Step-by-step explanation:

Given: A rocket is launched with speed 85 ft/s from a height 28  feet.

Launching a rocket follows the path of parabola. The equation of rocket should be parabolic.

Parabolic equation of rocket is

Formula: h(t)=\dfrac{1}2gt^2+v_0t+h_0

g ⇒ acceleration due to gravity (-32 ft/s)

v ⇒ Initial velocity (v_0=85\ ft/s)

h ⇒ Initial height (h_0=28\ feet)

h(t) ⇒ function of height at any time t

Substitute the given values into formula

h(t)=\frac{1}{2}(-32)t^2+(85)t+28

h(t)=-16t^2+85t+28

D is correct.

6 0
3 years ago
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How do you write y=25x-56 in standard form?
Tcecarenko [31]
To put a slope-intercept into standard form, you have to first cancel out the fractions. So:
y = \frac{2}{5}x - \frac{5}{6}

Turns into:
(5)(6)y = (\frac{2}{5}x - \frac{5}{6})(5)(6)

Simplify:
30y =  (\frac{2}{5}x - \frac{5}{6})(30)

Distribute:
30y = 12x- 25

Since you want to get x and y on the same side, you subtract 12x from both sides to get:
-12x+30y = -25

So, your answer is C. Hope this all made sense! If it doesn't you know where to get a hold of me, so just dm me. Or if you more problems.
6 0
4 years ago
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