take a pic of what and where are the questions???
Complete the table for the function y = 0.1^x
The first step: plug values from the left column into the ‘x’ spot in the formula <u>y=0.1^x</u>.
* 0.1^-2 : We can eliminate the negative exponent value by using the rule a^-1 = 1/a. Keep this rule in mind for future problems. (0.1^-2 = 1/0.1 * 0.1 = 100).
* 0.1^-1 = 1/0.1 = 10
* 0.1^0 = 1 : (Remember this rule: a^0 = 1)
* 0.1^1 = 0.1
Our list of values: 100, 10, 1, 0.1
Now, we can plug these values into your table:
![\left[\begin{array}{ccc}x&y\\2&10\\1&10\\0&1\\1&0.1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx%26y%5C%5C2%2610%5C%5C1%2610%5C%5C0%261%5C%5C1%260.1%5Cend%7Barray%7D%5Cright%5D)
The points can now be graphed. I will paste a Desmos screenshot; try to see if you can find some of the indicated (x,y) values: [screenshot is attached]
I hope this helped!
12,14,16
You reduce similar terms ("n" and numbers) then you just simplify the equation and kind of guess the even numbers that equal 42 based on your answer (12)
Data is collected on the types of vehicles
this is cross sectional data
Time is not relavant for this data and hence cannot be time series data.
b)
from the given information, the variable is type of vehicle which is categorical data
c)
this data is only about the more frequent vehicles the chain cannot ignore the vehicles which are not parked
Answer:
x=-1/4+i*sqrt(47)/4 and x=x=-1/4-i*sqrt(47)/4
Step-by-step explanation:
Using quadratic formula, x=(-1±sqrt(1-48))/4.
x=-1/4+i*sqrt(47)/4 and x=x=-1/4-i*sqrt(47)/4