Solve for x over the real numbers:
3 x^2 + 5 x + 1 = 0
Hint: | Using the quadratic formula, solve for x.
x = (-5 ± sqrt(5^2 - 4×3))/(2×3) = (-5 ± sqrt(25 - 12))/6 = (-5 ± sqrt(13))/6:
Answer: x = (-5 + sqrt(13))/6 or x = (-5 - sqrt(13))/6
AD || BC and BD is the transversal,
Therefore, angle DBC = angle ADB = 42° [alternate angles]
AD || BC and BD is the transversal,
angle BAD + angle ABD + angle DBC = 180° [co-interior angles]
or, 106°+ angle ABD + 42° = 180°
or, 148° + angle ABD = 180°
or, angle ABD = 180°-148° = 32°
Therefore, angle ABC = (32+42)° = 74°
AB||CD and BC is the transversal,
angle ABC + angle BCD = 180° [co-interior angles]
or, 72+2x+12 = 180
or, 84+2x = 180
or, 2x=180-84 = 96
or, x = 48
Answers: a)48°
b)42°
c)72°
The milk is the dependent variable
The two equivalent equations are d₁= 2a/d₂ and d₂= 2a/d₁ , Option 2 and 5 is the right answer.
<h3>What is a Rhombus ?</h3>
Rhombus is a quadrilateral with all the sides equal to each other.
It is given that d₁ and d₂ are the lengths of the diagonals.
and Area = a
a = (1/2) d₁ * d₂
d₁ * d₂ = 2a
It can be written as
d₁= 2a/d₂
a = (1/2) d₁ * d₂
d₂= 2a/d₁
Therefore Option 2 and 5 are the correct answer.
The options of this question are:
1. d₁=2Ad₂
2. d₁= 2A/d₂
3. d₂= d₁/2A
4. d₁= 2A/d₂
5. d₂= 2A/d₁
To know more about Rhombus
brainly.com/question/27870968
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