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3 years ago

What is term for convincing a customer to buy a larger quantity of an item or a more expensive item?

2 answers:

4 0

Up selling, pretty much to increase profits made by the store by tricking the customer into buying more expensive products.

uranmaximum [27]3 years ago

3 0

Upselling. As the dictionary states, "Upselling is a sales technique where a seller induces the customer to purchase more expensive items, upgrades or other add-ons in an attempt to make a more profitable sale."

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you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

3 years ago

Can someone please help me with this question please ?

EleoNora [17]

Answer:

x=43

Step-by-step explanation:

Since the lines are parrallel, the angle underneath the one you are finding is equal to 65. To find the total value of (x+72) you subtract 65 from 180, giving you 115.

x+72 = 115

then you subtract 72 from both sides

x=43

8 0

3 years ago

- Explain how you would start to solve the given system of equations below:

pychu [463]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

If a data value is 2 and the mean is 11, what is the associated<br> deviation?

Westkost [7]

Answer:

the mean = 9, and the mean deviation = 3.75

Hope this helps! :)

3 0

2 years ago

Help. I need to factor and solve using the quadratic formula <br>-x^2+2x=7

aleksandrvk [35]

Answer:

Irreducible factorization

Step-by-step explanation:

7 0

3 years ago