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erik [133]
3 years ago
15

Which ordered pair is a solution to the equation 3y=-2x-4

Mathematics
1 answer:
sveticcg [70]3 years ago
3 0

Answer:

ouoi

Step-by-step explanation:

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Which graph represents the function f(x) = |x + 3| ?
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Answer:

Step-by-step explanation:

Si haces una fracción buscando su denominador te da resultados

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In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving that lines
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3 years ago
Math help please thanks
Pepsi [2]
For most of these questions, all you would have to do is add the angles together and or subtract the larger angle from the smaller one to find the other angle. So in the first case.

You would add the angles, 26 degrees and 60 degrees to find the angle KLM which is about 90 degrees a right angle, in this case it would be 86 degrees.

Similarly, for the other question, take the larger angle, 145 degrees and subtract 61 degrees to solve for the angle that will also add to give 145 degrees,in this case it would be 84 degrees.

3 0
3 years ago
find the derivative with respect to x of f(x)=4x , and use it to find the equation of the tangent line to y=4x at x= 5
seropon [69]

Answer:

F(x)=4X X=5

F(5)=4X

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4 0
2 years ago
The number of customers waiting for gift-wrap service at a department store is an rv X with possible values 0, 1, 2, 3, 4 and co
julia-pushkina [17]

Answer:

P[X=3,Y=3] = 0.0416

Step-by-step explanation:

Solution:

- X is the RV denoting the no. of customers in line.

- Y is the sum of Customers C.

- Where no. of Customers C's to be summed is equal to the X value.

- Since both events are independent we have:

                         P[X=3,Y=3] = P[X=3]*P[Y=3/X=3]

              P[X=3].P[Y=3/X=3] = P[X=3]*P[C1+C2+C3=3/X=3]

        P[X=3]*P[C1+C2+C3=3/X=3] = P[X=3]*P[C1=1,C2=1,C3=1]        

              P[X=3]*P[C1=1,C2=1,C3=1]  = P[X=3]*(P[C=1]^3)

- Thus, we have:

                        P[X=3,Y=3] = P[X=3]*(P[C=1]^3) = 0.25*(0.55)^3

                        P[X=3,Y=3] = 0.0416

6 0
3 years ago
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