The distribution of means is the correct comparison distribution when
Answer: The distribution of means is the correct comparison distribution when there is more than one person in a sample.
The distribution of the sample means is also called the sampling distribution of mean. It is most appropriate when we take a random sample of size n from the population of size N. The distribution of the sample means will follow normal distribution with mean =
and standard deviation =
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Algebra II</u>
- Distance Formula:

Step-by-step explanation:
<u>Step 1: Define</u>
Point (5, -6)
Point (-3, 12)
<u>Step 2: Find distance </u><em><u>d</u></em>
Simply plug in the 2 coordinates into the distance formula to find distance<em> d</em>
- Substitute in points [Distance Formula]:

- [√Radical] (Parenthesis) Subtract/Add:

- [√Radical] Evaluate Exponents:

- [√Radical] Add:

- [√Radical] Simplify:

Answer: 0.444225
Step-by-step explanation:
Given : The total number of tickets = 50
Number of tickets are randomly sampled without replacement =6
Since the order of selection is not important , so we use combinations.
Total number of ways to select 6 tickets = 
The number of winning tickets = 6
So, number of tickets that are not winning = 50-6=44
Number of ways of selecting zero winning numbers= 
Now , the probability of holding a ticket that has zero winning numbers out of the 6 numbers selected for the winning ticket out of the 50 possible numbers would be 

Hence, the required probability = 0.444225
Meg makes a dot plot for the data 9, 9, 4, 5, 5, 3,<br>
4,5, 3, 8, 8, 5. Where does a gap occur?
Papessa [141]
The gap consists of the values 6 and 7.
Check out the dot plot below to see what I mean. We have one cluster on the left from 3 to 5. Then another cluster on the right from 8 to 9.
To solve the two sets of equations simultaneously, subtract one equation from the other to obtain
3x^5 + 2x^2 - 10x + 4 - (4x^4 + 6x^3 - 11) = 0
3x^5 - 4x^4 - 6x^3 + 2x^2 - 10x - 7 = 0
This is a polynomial of degree 5 to be solved for zeros.
A graphing calculator will yield 3 real zeros (verifiable by Descartes Rule of Signs).