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3 years ago

Pls help with trig ✋

Mathematics

1 answer:

Firdavs [7]3 years ago

8 0

Step-by-step explanation:

From Pythagorean theorem

x^2 = (10)^2 - (8)^2 = 36 or x =6

sin theta = opp/hyp = 6/10 = 3/5

cos theta = adj/hyp = 8/10 = 4/5

tan theta = opp/adj = 6/8 = 3/4

cot theta = 1/tan theta = 4/3

sec theta = 1/cos theta = 5/4

csc theta = 1/sin theta = 5/3

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There are 28.35 grams in an ounce and 2.21 pounds in a kilogram. Miriam converted 7 kilograms to ounces, but her answer is not c

Montano1993 [528]

Answer:

The conversion from kilograms to ounce

Step-by-step explanation:

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3 years ago

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2 years ago

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Which statement is true about the extreme value of the given quadratic equation? y=-3x2+12x-33 A. The equation has a minimum val

svp [43]

Given quadratic equation : $y=-3x^2+12x-33$ .

A quadratic equation represents a parabola.

We have leading coefficient is -3, a negative number.

So, it would be a downward parabola and it would have it's vertex point on the top on the parabola.

So, it would obviously have a maximum value.

Let us find the x-coordinate of the parabola first and then y-coordinate of the parabola.

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3 years ago

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3 years ago

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Given: ST ║ RP , SD ⊥ PR , SP = TR, SD = 5, ST = 15, PR = 24 Find: m∠P, m∠PST, m∠T, m∠R, PS, TR

makkiz [27]

Answer:

Part 1) $m\angle P=48.01^o$

Part 2) $m\angle PST=131.99^o$

Part 3) $m\angle T=131.99^o$

Part 4) $m\angle R=48.01^o$

Part 5) $PS=\sqrt{45.25}\ units$ , or $PS=6.7\ units$

Part 6) $TR=\sqrt{45.25}\ units$ , or $TR=6.7\ units$

Step-by-step explanation:

see the attached figure to better understand the problem

In this problem we have an isosceles trapezoid

Part 1) Find the measure of angle P

Find the value of side PD

we have that

$PR=PD+ER+ST$ ---> by addition segment postulate

$PD=ER$ ----> by isosceles trapezoid

$PR=2PD+ST\\PD=(PR-ST)/2$

substitute the given values

$PD=(24-15)/2$

$PD=4.5\ units$

In the right triangle PSD

$tan(P)=\frac{SD}{PD}$

$P=tan^{-1}(\frac{SD}{PD})$

substitute the given values

$m\angle P=tan^{-1}(\frac{5}{4.5})$

$m\angle P=48.01^o$

Part 2) Find the measure of angle PST

we know that

In a trapezoid ST ║ RP

$m\angle P+m\angle PST=180^o$ ---> by consecutive interior angles

we have

$m\angle P=48.01^o$

substitute

$48.01^o+m\angle PST=180^o$

$m\angle PST=180^o-48.01^o$

$m\angle PST=131.99^o$

Part 3) Find the measure of angle T

we know that

In this problem we have an isosceles trapezoid

$m\angle T=m\angle S$

we have

$m\angle PST=m\angle S=131.99^o$

therefore

$m\angle T=131.99^o$

Part 4) Find the measure of angle R

we know that

In this problem we have an isosceles trapezoid

$m\angle R=m\angle P$

we have

$m\angle P=48.01^o$

therefore

$m\angle R=48.01^o$

Part 5) Find the measure of segment PS

we know that

In the right triangle PSD

Applying the Pythagorean Theorem

$PS^2=SD^2+PD^2$

substitute the given values

$PS^2=5^2+4.5^2$

$PS^2=45.25$

$PS=\sqrt{45.25}\ units$

$PS=6.7\ units$

Part 6) Find the measure of segment TR

we know that

TR=PS ---> by isosceles trapezoid

we have

$PS=\sqrt{45.25}\ units$

therefore

$TR=\sqrt{45.25}\ units$

$TR=6.7\ units$

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4 years ago