Answer:
The length of AE is 20 units.
Step-by-step explanation:
Given two segments AD and BC intersect at point E to form two triangles ABE and DCE. Side AB is parallel to side DC. A E is labeled 2x+10. ED is labeled x+3. AB is 10 units long and DC is 4 units long.
we have to find the length of AE
AB||CD ⇒ ∠EAB=∠EDC and ∠EBA=∠ECD
In ΔABE and ΔDCE
∠EAB=∠EDC (∵Alternate angles)
∠EBA=∠ECD (∵Alternate angles)
By AA similarity, ΔABE ≈ ΔDCE
therefore, 
⇒ 
⇒ 
⇒ 
Hence, AE=2x+10=2(5)+10=20 units
The length of AE is 20 units.
Answer: 2nd and 6th options are correct
Step-by-step explanation: It showed me after I got em wrong
The system of linear inequalities x + 10y ≤ 80, x ≥ 30 and y ≤ 4 is represented in a graph below
<h3>Graph of Linear Inequality</h3>
The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality.
To solve this problem, we would require the use of graph which can easily be done with a graphing calculator.
x + 10y ≤ 80
x ≥ 30
y ≤ 4
The graph of the inequalities is attached below
Learn more on graph of linear inequality here;
brainly.com/question/19443475
#SPJ1
<u><em>Answer:</em></u>
15(1+3)
<u><em>Explanation:</em></u>
<u>The distributive property can be generally expressed as follows:</u>
ab + ac = a(b+c)
<u>The given expression is:</u>
15 + 45
<u>We know that:</u>
15 = 1*15
45 = 3*15
<u>Therefore, the given expression can be written as:</u>
1*15 + 3*15
<u>Taking 15 as a common factor and applying the above rule, we will reach the following expression:</u>
15(1+3)
Hope this helps :)
