Answer:
Drive reduction theory is the idea that a phycological need creates an aroused state that drives the organism to reduce the need by doing the desired act. homeostasis is the physiological aim of drive reduction, homeostasis is the maintenance of a steady internal state. Incentives are positive or negative stimuli that lure or repel us from reducing drives. Optimal arousal theory says that some motivational behaviors actually increase arousal. last of all, Maslow's hierarchy of needs, a pyramid diagram showing our needs on each level, going from physiological to self transcendence.
Explanation:
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Answer
B) 2041
Explanation:
The rate of growth per year is 1.2% which means after first year the population will be
7+ 7×(1.2/100)
After second year
7×1.012 +7×1.012 (1.2/100)
=7×1.012 (1+1.2/100)
=7×1.012 (1.012)
=7×1.012 ×1.012
Similarly, after third year it will be as:
=7×1.012 ×1.012 ×1.012
So our after x year the growth will be
7 (1.012)^x
We need to find, when the value will be 10 billion so our equation will be as:
10=7×(1.012)^x
We can solve it easily here.
10/7= (1.012)^x
Take log on both sides
㏒ 10/7 = ㏒(1.012^x)
㏒ 10/7 = ㏒(1.012^x)
㏒ 10/7 ÷㏒(1.012) = x
x =29.90 ≈ 30
Conclusion:
So it will take 30 years to take the world population to reach 10 billion if the rate of growth is 1.2%. Thus 2011 + 30 = 2041 is the correct answer.
You can never truly resolve a matter of opinion, however you can come to an agreement based on the facts and each other opinions
The answer is Eastern European
Explanation:
Subdividing [0, 1] into 10 equally spaced intervals of length 
gives the partition
![[0,1] = \left[0,\dfrac1{10}\right] \cup \left[\dfrac1{10},\dfrac2{10}\right] \cup \cdots \cup \left[\dfrac9{10},1\right]](https://tex.z-dn.net/?f=%5B0%2C1%5D%20%3D%20%5Cleft%5B0%2C%5Cdfrac1%7B10%7D%5Cright%5D%20%5Ccup%20%5Cleft%5B%5Cdfrac1%7B10%7D%2C%5Cdfrac2%7B10%7D%5Cright%5D%20%5Ccup%20%5Ccdots%20%5Ccup%20%5Cleft%5B%5Cdfrac9%7B10%7D%2C1%5Cright%5D)
The 
-th subinterval has left and right endpoints, respectively, given by
where 
.
The midpoint of the -th interval is the average of these,
We approximate the area under 
over [0, 1] by the Riemann sum,
(D)
