You didn't put any function to describe
The greatest possible area with a fixed length of fencing (perimeter) is a circle.
Circumference = 2 pi x radius = 24 m
Radius = (24 m) / (2 pi) = 12 m / pi
Area of a circle = pi x radius squared = (pi) x (12 m / pi)^2 = 144 / pi = 45.837 square meters.
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The rectangle with the greatest possible area for a fixed perimeter is the square.
Each side of the square = 24 / 4 = 6 meters
Area of a square = (side) squared = 36 square meters
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There is no 'least possible' area. The longer and skinnier you make it,
the less area it will have.
Here are some examples. Each one has 24 m of fencing:
5 m x 7 m = 35 square meters
4 x 8 = 32 square meters
3 x 9 = 27 square meters
2 x 10 = 20 square meters
1 x 11 = 11 square meters
0.5 x 11.5 = 5.75 square meters
0.1 x 11.9 = 1.19 square meters
1 centimeter x 11.99 meters = 0.1199 square meters
1 millimeter by 11.999 meters = 0.011999 square meters
The longer and skinnier the garden is, the less area it has.
Step-by-step explanation:
Let the midpoint formula be expressed as;
M(X,Y) = {x2+x1/2, y2+y1/2}
X = x2+x1/2
Y = y2+y1/2
Get x2
-3 = x2 + 1/2
-6 = x2 + 1
x2 = -6-1
x2 = -7
Get y2;
Y = y2+y1/2
8 = y2+6/2
16 = y2+6
Y2 = 16-6
y2 = 10
hence the coordinate of B is (-7, 10). Option A is correct
