We have to draw the model for 42 divide 7 . In order to draw the model we use below steps.
- Draw 7 boxes to represent 7 groups.
- Assume 42 as the number which represents the total of these 7 groups.
- Put a question mark at the first box.
Attached is the model to represents 42 divide 7 .
In the question mark we should put 6. Hence, when we add 6 to 7 times that will be equal to 42.
(1/5)/(5)=(1/5)(1/5)=1/25 of a pack of seeds will be planted in each pot
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Answer:
x= 0 , 
, 
Step-by-step explanation:
Given, equation is ![\sqrt[3]{15x-1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B15x-1%7D)
+ ![\sqrt[3]{13x+1}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B13x%2B1%7D)
= ![4\sqrt[3]{x}](https://tex.z-dn.net/?f=4%5Csqrt%5B3%5D%7Bx%7D)
. →→→ (1)
Now, by cubing the equation on both sides, we get
( + )³ = ()³
⇒ (15x-1) + (13x+1) + 3×× ( + ) = 64 x.
⇒ 28x + 3×× () = 64x.
(since from (1), + = )
⇒ 12× × (![\sqrt[3]{x}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D)
)= 36x.
⇒ 3x = ![\sqrt[3]{(15x-1)(13+1)(x)}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%2815x-1%29%2813%2B1%29%28x%29%7D)
.
Now, once again cubing on both sides, we get
(3x)³ = ()³.
⇒ 27x³ = (15x-1)(13x+1)(x).
⇒ 27x³ = 195x³ + 2x² - x
⇒ 168x³ + 2x² - x = 0
⇒ x(168x² + 2x -1) = 0
⇒ by, solving the equation we get ,
x = 0 ; x = ; x =
therefore, solution is x= 0 , ,
Since the minimum value is 0 and axis of symmetry is -2 this means that the vertex is at -2,0 now with the y intercept of 4. You can now plug the values into Vertex form which will be y=a(x-h)^2+k. a being the shrink or stretch of the parabola, h being the x value of the vertex, and k being the y value of the vertex. with all of that plugged in it should look like y=(x+2)^2. You can check this equation by plugging in 0 as x which should find the y intercept of 4. So it should then look like y=(0+2)^2 -> y=(2)^2 -> y=4
